Given the reaction mechanism and the quantities listed below, find the limiting reagent and the theoretical yield of the given reaction:0.5 grams 2-naphthol (weight: 114.17 g/mol)0.2 grams KOH (weight: 56.11 g/mol)30 mL iodoethane (weight: 155.97 g/mol, density: 1.94 g/mL) The image depicts a chemical reaction process.**Reactants:**1. **1-Naphthol (C₁₀H₇OH):** Illustrated on the left with a naphthalene ring structure and a hydroxyl group (OH) attached.2. **Ethyl iodide (C₂H₅I):** Shown as a simple ethyl group (C₂H₅) attached to an iodine (I) atom.**Reagents and Conditions:**- **Potassium hydroxide (KOH):** Used in this reaction as a base.- **Ethanol:** Serves as the solvent.**Reaction Process:**- The 1-naphthol reacts with ethyl iodide in the presence of potassium hydroxide in ethanol.**Products:**1. **Nerolin (Ethyl naphthyl ether):** The main product, shown on the right. It's characterized by an ethyl group (C₂H₅) connected to the oxygen that links to the naphthalene ring.2. **Water (H₂O):** A byproduct formed during the reaction.3. **Potassium iodide (KI):** Another byproduct formed in the process.This reaction showcases the formation of an ether from an alcohol and an alkyl halide, commonly referred to as the Williamson ether synthesis.

Limiting agent:- Limiting agents are those which totally convert into a product and determine the amount of product that has produced. Theoretical yield:- The quantity of products that can be got from the limiting reagent is called theoretical yield. (Mass = Volume× density) Calculation of theoretical yield:- From the above reaction, 2-naphthol is the limiting reagent. So, 114.17 g of 2-naphthol gives 172.22 g of nerolin. 0.5 g of 2-naphthol gives 172.22114.17×0.5 =0.75 g nerolin. Theoretical yield = 0.75 g