Given the power series expression E n A xln + 2) n = 1 + 2 3 A x" n = 1 1. Force the first power series to have a simple exponent. 2. Make sure that the power series start at the same value for n. 3. Combine the two power series together into a single power series. 00 (A R = 1 00 ® 2 [3 (R - 2) A, ] * B R = 1 © 34, x' + 6A,x2 + E [3RA * Σ R = 3 00 E (R - 2) A (a - 2) + 34,]* ЗА R = 1 00 ® 34, x! + 3A, x² + 2 [[R - 2) A (r - 2) + 3 A (R- 2) R = 3 00 © -34, + E [3(r - 2) A ] =* E [3 (R – 2) A,] × (F R = 3
Given the power series expression E n A xln + 2) n = 1 + 2 3 A x" n = 1 1. Force the first power series to have a simple exponent. 2. Make sure that the power series start at the same value for n. 3. Combine the two power series together into a single power series. 00 (A R = 1 00 ® 2 [3 (R - 2) A, ] * B R = 1 © 34, x' + 6A,x2 + E [3RA * Σ R = 3 00 E (R - 2) A (a - 2) + 34,]* ЗА R = 1 00 ® 34, x! + 3A, x² + 2 [[R - 2) A (r - 2) + 3 A (R- 2) R = 3 00 © -34, + E [3(r - 2) A ] =* E [3 (R – 2) A,] × (F R = 3
Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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q13
![Given the power series expression
Σ
n A x(n + 2)
n = 1
3 A x"
n = 1
1. Force the first power series to have a simple exponent.
2. Make sure that the power series start at the same value for n.
3. Combine the two power series together into a single power series.
A
3 RA
x*
R = 1
00
© ( - 2) A,"
B
R = 1
3A, x + 6A,x² +
RA
R = 3
00
D
O (R - 2) A (x - 2) + 34] **
(R- 2)
R = 1
E 3 A, x' + 3 A, x² +
E [(R - 2) A (R - 2) + 3A,
R = 3
® -34, x' + E [3(R – 2) A„ ] ×*
F
R = 3](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F25002bdf-f87e-4b90-9220-df81045dfb4e%2F59c60781-084a-4a00-9fae-0b215bee1f9c%2Fpntv0uh_processed.jpeg&w=3840&q=75)
Transcribed Image Text:Given the power series expression
Σ
n A x(n + 2)
n = 1
3 A x"
n = 1
1. Force the first power series to have a simple exponent.
2. Make sure that the power series start at the same value for n.
3. Combine the two power series together into a single power series.
A
3 RA
x*
R = 1
00
© ( - 2) A,"
B
R = 1
3A, x + 6A,x² +
RA
R = 3
00
D
O (R - 2) A (x - 2) + 34] **
(R- 2)
R = 1
E 3 A, x' + 3 A, x² +
E [(R - 2) A (R - 2) + 3A,
R = 3
® -34, x' + E [3(R – 2) A„ ] ×*
F
R = 3
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