q17 Given the power series2 n (n - 1) A x (n + 2)n =1Use the technique that we covered in this lesson to Shift the Index of the Power Series so that the exponent of the power series issimplified.00A)ΣE n (n - 1) A x" + 2) becomes2 (R + 2)? A (r + 2) **n =1n = 1B R2 A, xk2 n (n - 1) A x" + 2) becomesRn =1n = 0002 n (n - 1) A x" + 2) becomesn =1n = 30000E n (n - 1) A x + 2) becomesE (R2 + 2R) A, x*n =1n = 0> n (n - 1) A x" + 2) becomesE (R - 2) (R - 3) A (R – 2)En =1n = 300F)Σ2n (n - 1) A x" + 2) becomes 2 (R + 2)2 A (R + 2)Σ (R+ 2)?n =1n = 3

In this question we shift the index so that the exponent of the power series is simplified . Note :…

Given the power series En (n - 1) A, xla + 2) n =1 Use the technique that we covered in this lesson to Shift the Index of the Power Series so that the exponent of the power series is simplified. A 2 n (n - 1) A xm + 2) becomes (R + 2)² A (R + 2) * n =1 n =1 (n - 1) A xla + 2) becomes R2 A, n =1 n =0 En (n - 1) A, xlu + 2) becomes E n =1 n = 3 O 2n (n - 1) A xa + 2) becomes E (R2 + 2R) A n =1 n = 0 En (n - 1) A xlu + 2) becomes (R - 2) (R – 3) A (R - 2) ** n =1 n = 3

Given the power series En (n - 1) A, xla + 2) n =1 Use the technique that we covered in this lesson to Shift the Index of the Power Series so that the exponent of the power series is simplified. A 2 n (n - 1) A xm + 2) becomes (R + 2)² A (R + 2) * n =1 n =1 (n - 1) A xla + 2) becomes R2 A, n =1 n =0 En (n - 1) A, xlu + 2) becomes E n =1 n = 3 O 2n (n - 1) A xa + 2) becomes E (R2 + 2R) A n =1 n = 0 En (n - 1) A xlu + 2) becomes (R - 2) (R – 3) A (R - 2) ** n =1 n = 3

Algebra & Trigonometry with Analytic Geometry

13th Edition

ISBN:9781133382119

Author:Swokowski

Publisher:Swokowski

Chapter10: Sequences, Series, And Probability

Section10.1: Infinite Sequences And Summation Notation

Problem 73E

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