Given the power series 2 (n + 2) A x(n + 1) n = 0 1. Force the Exponent "n + 1" to be "R" like we did in the last lesson. 2. Now use what we have learned in this lesson to force the new series to start at "R = 3". 00 00 A E (n + 2) A, x(n + 1) 1) A (R - 1) * n = 0 R = 0 00 00 B 2 (n + 2) A x(n +1) E (R + 1) A (R - 1) * n =0 R = 1 E (n + 2) A x(n + 1) = E (R- 1) A R -) (R- 1) n = 0 R = -1 00 00 (D 2 (n + 2) A x(n + 1) Σ (R+2) A n = 0 R = 0 00 E (n + 2) A_ xln + 1) I (R + 3) A E (R +1) n = 0 R = 1 00 E (n + 2) A, xla + 1) Ž (R + 3) Ag x* (F) n = 0 R = 1
Given the power series 2 (n + 2) A x(n + 1) n = 0 1. Force the Exponent "n + 1" to be "R" like we did in the last lesson. 2. Now use what we have learned in this lesson to force the new series to start at "R = 3". 00 00 A E (n + 2) A, x(n + 1) 1) A (R - 1) * n = 0 R = 0 00 00 B 2 (n + 2) A x(n +1) E (R + 1) A (R - 1) * n =0 R = 1 E (n + 2) A x(n + 1) = E (R- 1) A R -) (R- 1) n = 0 R = -1 00 00 (D 2 (n + 2) A x(n + 1) Σ (R+2) A n = 0 R = 0 00 E (n + 2) A_ xln + 1) I (R + 3) A E (R +1) n = 0 R = 1 00 E (n + 2) A, xla + 1) Ž (R + 3) Ag x* (F) n = 0 R = 1
Algebra & Trigonometry with Analytic Geometry
13th Edition
ISBN:9781133382119
Author:Swokowski
Publisher:Swokowski
Chapter10: Sequences, Series, And Probability
Section10.2: Arithmetic Sequences
Problem 67E
Related questions
Question
q8
Transcribed Image Text:Given the power series
2 (n + 2) A xln + 1)
n = 0
1. Force the Exponent "n + 1" to be "R" like we did in the last lesson.
2. Now use what we have learned in this lesson to force the new series to start at "R = 3".
A E (n + 2) A, xu + 1) = 2 (R + 1) A (R - 1)
- 1)
n = 0
R = 0
00
00
®E (n + 2) A, xla + 1)
I (R + 1) A (R - 1)
n = 0
R = 1
C)
2 (n + 2) A x(n + 1)
E (R - 1) A (R - 1) **
n = 0
R = -1
00
00
DE (n + 2) A xlu + 1) =
E (R + 2) AR
n = 0
R = 0
00
00
E
2 (n + 2) A x (n + 1)
E (R + 3) A (R + 1) **
n = 0
R = 1
00
00
(F)
E (n + 2) A, x(u + !) = E (R + 3) A the
2 (R + 3) A, x*
n = 0
R = 1
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