Given the power series 2 (n + 2) A x(2n + 1) n =0 Use the technique that we covered in this lesson to force the series to start at "n = 3". A E (n + 2) A, x(2n + 1) = 5A, x³ + E (n + 2) A, (2n + 1) %3D n = 0 n = 3 B2 (n + 2) A¸ x(2n + 1) n = 0 00 A,x' + 24, x3 + 3A, x + E (n + 2) A x(2n + 1) n = 3 © 2 (n + 2) A x(2n + 1) n = 0 00 2 A,x' + 3A, x3 + 4A, x5 + E (n + 2) A x(2n + 1) n = 3 00 DE (n + 2) A, x 00 (2n + 1) = 1 + 2x' + 3x² + E (n + 2) A x(2n + 1) n = 3 EE (n + 2) A, x(2n + 1) = A, x2 n = 0 + A,x + 2 (n + 2) A x(2n + 1) %3D n= 3 00 P2 n = 0 E (n + 2) A x(2n + 1) = 2 + 3x2 + 4 x + E (n + 2) A x(2n + 1) n = 3

Q: 2(3y-5)=34

A: We will see the ans in next step

Q: V-539 7. V11

A: To Determine:  Simplify

Q: Find A. A = (3A)-1 [ -3-2 4 2

A: Let us consider that                     A=abcdWe have                   (3A)-1=-3-242 ⟹…

Q: 4y-12=0

A: 4y = 12 y = 3

Q: 1 L (s- 4)6 J

A:

Q: What is the value for s3?

A:

Q: 14 +2

A: Adding Fractions Step 1: Make sure the bottom numbers (the denominators) are the same. Step 2: Add…

Q: -12+(4• 3) (-) I 2-14 - 3)ENTER

A:

Q: 3b-12 = 30

A:

Q: 3n+20=15

A: solve the given 3n+20=15

Q: (-12)+7

A: To simplify any expression involving numbers we need to use the BODMAS rule which specifies the…

Q: Vs-+ 12²

A: To determine:

Q: 2(a+3)= -12

A: Solution: Here 2(a+3) =-12

Q: 8P4 11C7

A:

Q: 7k = 91

A: We will find the value of k in the following step.

Q: Find

A: We know that,                         ∫1xdx=lnx+ c We need to find  ∫4xdx

Q: -3(4x-5)-6=18

A: Given: −34x−5−6=18 To determine: The value of x.