Given the power series 2 A x2n Σ n = 0 Find the Derivative of the Power Series. (2n + 1) ΣΑ 00 d 00 A ΣΑ - 4, dx n = 0 n = 0 2n + 1 d 00 B 2 A x2n E A x(2n - 1) dx n = 0 n = 0 00 d 00 E A x2n dx 2 A 2n x(2n - 1) =D n = 0 n = 0 00 d (D Σ Α dx E A, (2n - 1) x(2n – 1) n = 0 n = 0 d 00 E 2 A x2n 2 2n x(2n - 1) dx n = 0 n = 0

Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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Given the power series
n = 0
Find the Derivative of the Power Series.
00
d
x (2n + 1)
(A)
dx
E A,
n = 0
2n + 1
d
00
B
= E A. x(2n - 1)
2n
A
dx
n = 0
n = 0
Σ
d
00
(c
A 2n
2 A 2n x(2n - 1)
dx
n = 0
n = 0
00
d
D
ΣΑ,
2n
E A, (2n – 1) x(2n – 1)
-
dx
n = 0
n = 0
00
d
00
E
2n
2 2n x(2n - 1)
dx
n = 0
n = 0
Transcribed Image Text:Given the power series n = 0 Find the Derivative of the Power Series. 00 d x (2n + 1) (A) dx E A, n = 0 2n + 1 d 00 B = E A. x(2n - 1) 2n A dx n = 0 n = 0 Σ d 00 (c A 2n 2 A 2n x(2n - 1) dx n = 0 n = 0 00 d D ΣΑ, 2n E A, (2n – 1) x(2n – 1) - dx n = 0 n = 0 00 d 00 E 2n 2 2n x(2n - 1) dx n = 0 n = 0
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