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Given the power series 2 2n A x(n + 3) n = 0 Use the technique that we covered in this unit to Shift the Index of the Power Series so that the exponent of the power series is simplified. A > x" 2 2n A x" + 3) becomes 2 2 R A, n = 0 R = 0 B E 2n A x" + 3) becomes 2 2 (R + 3) A (R + 3) * n = 0 R = 0 00 © E 2n A, xl" + 3) becomes 2 2 (R+ 3) A (R + 3) *"* n = 0 R = -3 00 ΟΣ E 2n A x(m + 3) becomes 2 (R - 3) A (R - 3) n = 0 R = 0 > 2n A x(n + 3) becomes 2 (R - 3) A R - 3) n =0 R = 3 00 2n A x(" + 3) becomes 2 (R + 3) A, xR n =0 R = 0

Given the power series 2 2n A x(n + 3) n = 0 Use the technique that we covered in this unit to Shift the Index of the Power Series so that the exponent of the power series is simplified. A > x" 2 2n A x" + 3) becomes 2 2 R A, n = 0 R = 0 B E 2n A x" + 3) becomes 2 2 (R + 3) A (R + 3) * n = 0 R = 0 00 © E 2n A, xl" + 3) becomes 2 2 (R+ 3) A (R + 3) *"* n = 0 R = -3 00 ΟΣ E 2n A x(m + 3) becomes 2 (R - 3) A (R - 3) n = 0 R = 0 > 2n A x(n + 3) becomes 2 (R - 3) A R - 3) n =0 R = 3 00 2n A x(" + 3) becomes 2 (R + 3) A, xR n =0 R = 0

Calculus: Early Transcendentals
Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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Given the power series 2 2n A x(m + 3) n = 0 Use the technique that we covered in this unit to Shift the Index of the Power Series so that the exponent of the power series is simplified. 00 A > 2n A x" + 3) becomes 2 2 R A, x" n = 0 R = 0 B 2 2n A E 2n A x" + 3) becomes 2 2 (R + 3) A (R + 3) (n + 3) n = 0 R = 0 00 2 2n A x(n + 3) 2 2 (R + 3) A (R + 3) ** becomes > n = 0 R = -3 00 Σ Α, 2 2n A x(m (n + 3) becomes E 2 (R - 3) A (R - 3) ** n = 0 R = 0 E > 2n A x" + 3) becomes 2 (R - 3) A (R - 3) n = 0 R = 3 2n A x" + 3) becomes 2 2(R + 3) A, x* n = 0 R = 0
Transcribed Image Text:Given the power series 2 2n A x(m + 3) n = 0 Use the technique that we covered in this unit to Shift the Index of the Power Series so that the exponent of the power series is simplified. 00 A > 2n A x" + 3) becomes 2 2 R A, x" n = 0 R = 0 B 2 2n A E 2n A x" + 3) becomes 2 2 (R + 3) A (R + 3) (n + 3) n = 0 R = 0 00 2 2n A x(n + 3) 2 2 (R + 3) A (R + 3) ** becomes > n = 0 R = -3 00 Σ Α, 2 2n A x(m (n + 3) becomes E 2 (R - 3) A (R - 3) ** n = 0 R = 0 E > 2n A x" + 3) becomes 2 (R - 3) A (R - 3) n = 0 R = 3 2n A x" + 3) becomes 2 2(R + 3) A, x* n = 0 R = 0
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