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Given the potential, V = 100(x² - y2), find p, P(2, -1, 3).

Given the potential, V = 100(x² - y2), find p, P(2, -1, 3).

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electromagnetic field)I want a detailed solution because my teacher changes the numbers. I want a detailed solution. Understand the solution
Example Given the potential, V = 100(x² - y²), find p, P(2, -1, 3). V₂ = 100((2)² – (-1)²) = 300 V Conductor surface is equipotential ⇒ The surface equation is 300=100(x² - y²) E=-V.V=-200xa Ep =-400a-200a, P x²-y²=3 +200 ya V/m Dp = Ep = -3.542a −1.771a¸ nC/m² DN = |D₂|= 3.96 nC/m² PS.P = DN = 3.96 nC/m² . Carefully examine the surface direction 1 0 -3 z = 3 plane 1 x²-y²=3 V-300 V xy=-2 3 P(2,-1,3)
Transcribed Image Text:Example Given the potential, V = 100(x² - y²), find p, P(2, -1, 3). V₂ = 100((2)² – (-1)²) = 300 V Conductor surface is equipotential ⇒ The surface equation is 300=100(x² - y²) E=-V.V=-200xa Ep =-400a-200a, P x²-y²=3 +200 ya V/m Dp = Ep = -3.542a −1.771a¸ nC/m² DN = |D₂|= 3.96 nC/m² PS.P = DN = 3.96 nC/m² . Carefully examine the surface direction 1 0 -3 z = 3 plane 1 x²-y²=3 V-300 V xy=-2 3 P(2,-1,3)
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