Given the points A=(3,-5,-2), B=(7,-1,1) and C=(-1,-1,4), the equation of the plane containing the points A, B, C, corresponds to: a) 12x – 36y + 32z = 152 - b) 36x – 180y – 64z = 152 - - c) 12x + 36y + 32z = -208 d) 36x + 180y – 64z = -208 |

Algebra and Trigonometry (6th Edition)
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ISBN:9780134463216
Author:Robert F. Blitzer
Publisher:Robert F. Blitzer
ChapterP: Prerequisites: Fundamental Concepts Of Algebra
Section: Chapter Questions
Problem 1MCCP: In Exercises 1-25, simplify the given expression or perform the indicated operation (and simplify,...
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Given the points A=(3,-5,-2), B=(7,-1,1) and C=(-1,-1,4), the equation of the plane containing the
points A, B, C, corresponds to:
a) 12x – 36y+32z = 152
b) 36x – 180y – 64z = 152
c) 12x + 36y+32z= –208
d) 36x + 180y – 64z = -208
Transcribed Image Text:Given the points A=(3,-5,-2), B=(7,-1,1) and C=(-1,-1,4), the equation of the plane containing the points A, B, C, corresponds to: a) 12x – 36y+32z = 152 b) 36x – 180y – 64z = 152 c) 12x + 36y+32z= –208 d) 36x + 180y – 64z = -208
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