Given the points A: (3, — 2, 2) and B: (5, 2, 6), find the vector u = AB

Calculus: Early Transcendentals
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Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
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### Find Vectors and Perform Vector Operations in \( \mathbb{R}^3 \)

Given the points \( A: (3, -2, 2) \) and \( B: (5, 2, 6) \), find the vector \( \vec{u} = \overrightarrow{AB} \).

\[ \vec{u} = \]

#### Explanation:
To find the vector \( \overrightarrow{AB} \), subtract the coordinates of point \( A \) from point \( B \).

- \( \overrightarrow{AB} = (x_2 - x_1, y_2 - y_1, z_2 - z_1) \)
- Calculate the component-wise differences:
  - \( x \)-component: \( 5 - 3 = 2 \)
  - \( y \)-component: \( 2 - (-2) = 4 \)
  - \( z \)-component: \( 6 - 2 = 4 \)

Therefore, the vector \( \vec{u} = \overrightarrow{AB} = (2, 4, 4) \).
Transcribed Image Text:### Find Vectors and Perform Vector Operations in \( \mathbb{R}^3 \) Given the points \( A: (3, -2, 2) \) and \( B: (5, 2, 6) \), find the vector \( \vec{u} = \overrightarrow{AB} \). \[ \vec{u} = \] #### Explanation: To find the vector \( \overrightarrow{AB} \), subtract the coordinates of point \( A \) from point \( B \). - \( \overrightarrow{AB} = (x_2 - x_1, y_2 - y_1, z_2 - z_1) \) - Calculate the component-wise differences: - \( x \)-component: \( 5 - 3 = 2 \) - \( y \)-component: \( 2 - (-2) = 4 \) - \( z \)-component: \( 6 - 2 = 4 \) Therefore, the vector \( \vec{u} = \overrightarrow{AB} = (2, 4, 4) \).
Expert Solution
Step 1

The points are given by

A3, -2, 2B5, 2, 6

To evaluate: The vector u = AB.

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