Given the parallel circuit presented below calculate the Equivalent Resistance Req when R1=400; R2=400 and R3=200. The Voltage of the battery is unknown. Battery R1 R2 R3

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**Question #10**

Given the parallel circuit presented below, calculate the Equivalent Resistance \( R_{eq} \) when \( R_1 = 40\Omega \); \( R_2 = 40\Omega \), and \( R_3 = 20\Omega \). The Voltage of the battery is unknown.

**Diagram Explanation:**

The diagram shows a parallel circuit powered by a battery. The circuit consists of three resistors labeled \( R_1 \), \( R_2 \), and \( R_3 \). 

- **Battery**: Depicted on the left, providing power to the circuit.
- **Resistors**: Arranged in parallel across the battery:
  - \( R_1 = 40\Omega \)
  - \( R_2 = 40\Omega \)
  - \( R_3 = 20\Omega \)

**Equivalent Resistance Calculation**:

In a parallel circuit, the Equivalent Resistance (\( R_{eq} \)) can be calculated using the formula:

\[
\frac{1}{R_{eq}} = \frac{1}{R_1} + \frac{1}{R_2} + \frac{1}{R_3}
\]

Substitute the values:

\[
\frac{1}{R_{eq}} = \frac{1}{40} + \frac{1}{40} + \frac{1}{20}
\]

Calculate each term:

\[
\frac{1}{R_{eq}} = \frac{1}{40} + \frac{1}{40} + \frac{1}{20} = \frac{1}{40} + \frac{1}{40} + \frac{2}{40} = \frac{4}{40} = \frac{1}{10}
\]

Therefore, the equivalent resistance is:

\[
R_{eq} = 10\Omega
\]
Transcribed Image Text:**Question #10** Given the parallel circuit presented below, calculate the Equivalent Resistance \( R_{eq} \) when \( R_1 = 40\Omega \); \( R_2 = 40\Omega \), and \( R_3 = 20\Omega \). The Voltage of the battery is unknown. **Diagram Explanation:** The diagram shows a parallel circuit powered by a battery. The circuit consists of three resistors labeled \( R_1 \), \( R_2 \), and \( R_3 \). - **Battery**: Depicted on the left, providing power to the circuit. - **Resistors**: Arranged in parallel across the battery: - \( R_1 = 40\Omega \) - \( R_2 = 40\Omega \) - \( R_3 = 20\Omega \) **Equivalent Resistance Calculation**: In a parallel circuit, the Equivalent Resistance (\( R_{eq} \)) can be calculated using the formula: \[ \frac{1}{R_{eq}} = \frac{1}{R_1} + \frac{1}{R_2} + \frac{1}{R_3} \] Substitute the values: \[ \frac{1}{R_{eq}} = \frac{1}{40} + \frac{1}{40} + \frac{1}{20} \] Calculate each term: \[ \frac{1}{R_{eq}} = \frac{1}{40} + \frac{1}{40} + \frac{1}{20} = \frac{1}{40} + \frac{1}{40} + \frac{2}{40} = \frac{4}{40} = \frac{1}{10} \] Therefore, the equivalent resistance is: \[ R_{eq} = 10\Omega \]
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