Given the mean and standard deviation of a normally distributed set of scores, determine the approximate location of the given scores in terms of the standard deviation. μ = 18; σ = 7; x = 35
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Given the mean and standard deviation of a
location of the given scores in terms of the standard deviation.
μ = 18; σ = 7; x = 35
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- Given the following mean and standard deviation, find the z-score for each individual score. Find the difference between the data value and the mean then divide by the standard deviation. X = 10 a. X= 8 s = 2 Z = %3D b. X= 38 X = 40 s = 5 Z = С. X%3D94 X = 100 s = 10 z = d. X= 65 X = 50 s = 10 Z = %3D e. X= 30 X = 25 s = 5 Z =Assume that a randomly selected subject is given a bone density test. Bone density test scores are normally distributed with a mean of 0 and a standard deviation of 1. Draw a graph and find P9, the 9th percentile. This is the bone density score separating the bottom 9% from the top 91%. Which graph represents P9? Choose the correct graph below.Find the area, square unit, to the nearest thousandth of the standard deviation between the given z-scores. Z equals 1.12 and z equals 1.73.
- Find the indicated IQ score. The graph to the right depicts IQ scores of adults, and those scores are normally distributed with a mean of 100 and a standard deviation of 15. The indicated IQ score is (Round to the nearest whole number as needed.) X 0.3949 oA data set lists weights (lb) of plastic discarded by households. The highest weight is 5.63 lb, the mean of all of the weights is x = 2.316 lb, and the standard deviation of the weights is s = 1.087 lb. a. What is the difference between the weight of 5.63 lb and the mean of the weights? b. How many standard deviations is that [the difference found in part (a)]? c. Convert the weight of 5.63 lb to a z score. d. If we consider weights that convert to z scores between 2 and 2 to be neither significantly low nor significantly high, is the weight of 5.63 lb significant? a. The difference is lb. (Type an integer or a decimal. Do not round.) Clear all Check awerStudents in a class took a test whose results were normally distributed. The mean score was an 81 and the standard deviation was 4.5. What score is at the 83rd percentile (round to the nearest whole number.) a.84 b.83 c.85 d.86
- Suppose baby kittens' weights are normally distributed with a mean of 11.4 and a standard deviation of 2.1. The Z-score tells you how many units above the average (if Z-score is positive) or below the average (if Z- Score is negative) any particular baby kitten's weight is. Find the baby kitten weight that corresponds to the following Z-scores. Use the formula Z where u is the mean, o is the standard deviation, and X is the baby kitten weight. a. Z = = 0.07, X = b. Z = 1.63, X =Assume that the readings at freezing on a batch of thermometers are normally distributed with a mean of 0°C and a standard deviation of 1.00°C. A single thermometer is randomly selected and tested. Find P70, the 70-percentile. This is the temperature reading separating the bottom 70% from the top 30%.P70 = °CIn a certain population, the mean score on a test is 420. The standard deviation is 105. If the distribution or scores is normal, which of these scores should occur most often. a. 385 b314 c. 540 d. 526
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