Given the linear system Ax = b 1 -1 -2 1.5 6.5 7.5 10.5 1 0 0 -1 1 0 0||0 1.5 2 1 0||0 o 1 3 [-2 –1.5 1 1][o _o o 1] 3 -1 2 [x1 b2 0][1 3 -1 21 4 w 5 0.25 X2 ,and A LU decomposition is A = X3 b3 [-2 –7.5 -3 -3.375][x4] If the system is solved using LU decomposition procedure and resulted in intermediate vector d = [ -1 1 0.5 2]" the constant vector b is equal to
Given the linear system Ax = b 1 -1 -2 1.5 6.5 7.5 10.5 1 0 0 -1 1 0 0||0 1.5 2 1 0||0 o 1 3 [-2 –1.5 1 1][o _o o 1] 3 -1 2 [x1 b2 0][1 3 -1 21 4 w 5 0.25 X2 ,and A LU decomposition is A = X3 b3 [-2 –7.5 -3 -3.375][x4] If the system is solved using LU decomposition procedure and resulted in intermediate vector d = [ -1 1 0.5 2]" the constant vector b is equal to
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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![Given the linear system Ax = b
1 3
-1
2
[X1]
1
0][1 3 -1 2]
-1
-2
5
0. 25
x2
b2
1
4 w
,and A LU decomposition is A = 1 1 0 0
b3
|1.5 2 1 0||0 o 1 3
[-2 -1.51 1J[0 o o 1]
1.5 6.5 7.5 10.5
x3
[-2 -7.5 -3 -3.375][x4]
If the system is solved using LU decomposition procedure and resulted in intermediate vector
d = [ -1 1 0.5 2]" the constant vector b is equal to](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F687d0573-33db-491b-a626-63465e831e85%2Fc1c1b7dd-fb9c-4737-aec7-bd089642b6d6%2Fw5gyscc_processed.png&w=3840&q=75)
Transcribed Image Text:Given the linear system Ax = b
1 3
-1
2
[X1]
1
0][1 3 -1 2]
-1
-2
5
0. 25
x2
b2
1
4 w
,and A LU decomposition is A = 1 1 0 0
b3
|1.5 2 1 0||0 o 1 3
[-2 -1.51 1J[0 o o 1]
1.5 6.5 7.5 10.5
x3
[-2 -7.5 -3 -3.375][x4]
If the system is solved using LU decomposition procedure and resulted in intermediate vector
d = [ -1 1 0.5 2]" the constant vector b is equal to
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