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Given the linear programming problem below where r represents the number of type A items produced and r2 the number of type B items produced. The first constraint is for the number of units of resource 1 available and the second is for the number units of resource 2 available. Max z = 6x1 +8x2 s.t. 1+2x2 < 120 I + 12 < 80 The solution is r1 = x2 = 40 with max z = 560. The final tableau is shown below. I2 81 82 rhs Basis 560 z = 560 12 = 40 40 0. 4. 1 1 -1 40 1 -1 I1 = 40 Use this information to answer the following questions. 2100

Given the linear programming problem below where r represents the number of type A items produced and r2 the number of type B items produced. The first constraint is for the number of units of resource 1 available and the second is for the number units of resource 2 available. Max z = 6x1 +8x2 s.t. 1+2x2 < 120 I + 12 < 80 The solution is r1 = x2 = 40 with max z = 560. The final tableau is shown below. I2 81 82 rhs Basis 560 z = 560 12 = 40 40 0. 4. 1 1 -1 40 1 -1 I1 = 40 Use this information to answer the following questions. 2100

Advanced Engineering Mathematics
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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Use the given picture to solve question 5. Please show all work and proper units. Thanks
Given the linear programming problem below where r1 represents the number of type A items produced and r2 the number of type B items produced. The first constraint is for the number of units of resource 1 available and the second is for the number units of resource 2 available. Max z = 6x1+8x2 s.t. 1+2x2 < 120 Ii + 12 < 80 The solution is r1 = x2 = 40 with max z = 560. The final tableau is shown below. I2 81 82 rhs Basis 0. 560 z = 560 0 0 0 1 1 1 -1 40 I2 = 40 -1 2 40 I1 = 40 Use this information to answer the following questions.
Transcribed Image Text:Given the linear programming problem below where r1 represents the number of type A items produced and r2 the number of type B items produced. The first constraint is for the number of units of resource 1 available and the second is for the number units of resource 2 available. Max z = 6x1+8x2 s.t. 1+2x2 < 120 Ii + 12 < 80 The solution is r1 = x2 = 40 with max z = 560. The final tableau is shown below. I2 81 82 rhs Basis 0. 560 z = 560 0 0 0 1 1 1 -1 40 I2 = 40 -1 2 40 I1 = 40 Use this information to answer the following questions.
5. Show that if the available number of units of resource 2 is between 60 and 120 the current basis remains optimal. tribute $10 to profits and would
Transcribed Image Text:5. Show that if the available number of units of resource 2 is between 60 and 120 the current basis remains optimal. tribute $10 to profits and would
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