Given the linear programming problem below where r represents the number of type A items produced and r2 the number of type B items produced. The first constraint is for the number of units of resource 1 available and the second is for the number units of resource 2 available. Max z = 6x1 +8x2 s.t. 1+2x2 < 120 I + 12 < 80 The solution is r1 = x2 = 40 with max z = 560. The final tableau is shown below. I2 81 82 rhs Basis 560 z = 560 12 = 40 40 0. 4. 1 1 -1 40 1 -1 I1 = 40 Use this information to answer the following questions. 2100
Given the linear programming problem below where r represents the number of type A items produced and r2 the number of type B items produced. The first constraint is for the number of units of resource 1 available and the second is for the number units of resource 2 available. Max z = 6x1 +8x2 s.t. 1+2x2 < 120 I + 12 < 80 The solution is r1 = x2 = 40 with max z = 560. The final tableau is shown below. I2 81 82 rhs Basis 560 z = 560 12 = 40 40 0. 4. 1 1 -1 40 1 -1 I1 = 40 Use this information to answer the following questions. 2100
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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Question
Use the given picture to solve question 5. Please show all work and proper units. Thanks
![Given the linear programming problem below where r1 represents the number of type A items produced and r2
the number of type B items produced. The first constraint is for the number of units of resource 1 available and the
second is for the number units of resource 2 available.
Max z = 6x1+8x2
s.t. 1+2x2 < 120
Ii + 12 < 80
The solution is r1 = x2 = 40 with max z = 560. The final tableau is shown below.
I2
81
82
rhs
Basis
0.
560 z = 560
0 0
0 1
1
1
-1
40
I2 = 40
-1
2
40
I1 = 40
Use this information to answer the following questions.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F12f9c0a0-4f48-4989-b5d4-e498b2b2b3d9%2F012f83b4-c76d-4439-ac47-e962bef26a12%2Fu4vlfri_processed.jpeg&w=3840&q=75)
Transcribed Image Text:Given the linear programming problem below where r1 represents the number of type A items produced and r2
the number of type B items produced. The first constraint is for the number of units of resource 1 available and the
second is for the number units of resource 2 available.
Max z = 6x1+8x2
s.t. 1+2x2 < 120
Ii + 12 < 80
The solution is r1 = x2 = 40 with max z = 560. The final tableau is shown below.
I2
81
82
rhs
Basis
0.
560 z = 560
0 0
0 1
1
1
-1
40
I2 = 40
-1
2
40
I1 = 40
Use this information to answer the following questions.
![5. Show that if the available number of units of resource 2 is between 60 and 120 the current basis remains optimal.
tribute $10 to profits and would](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F12f9c0a0-4f48-4989-b5d4-e498b2b2b3d9%2F012f83b4-c76d-4439-ac47-e962bef26a12%2F99x8n5m_processed.jpeg&w=3840&q=75)
Transcribed Image Text:5. Show that if the available number of units of resource 2 is between 60 and 120 the current basis remains optimal.
tribute $10 to profits and would
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