GIVEN: The line, L, parameterized by the path c: R → R³, given by = č(t) = (1+2t, 2+t, 3+ 2t); and the point P (1, 0, 4). FIND: The distance from P to L, d(P, L).
GIVEN: The line, L, parameterized by the path c: R → R³, given by = č(t) = (1+2t, 2+t, 3+ 2t); and the point P (1, 0, 4). FIND: The distance from P to L, d(P, L).
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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Question
For the first image attached please do the calculations similar to the second image attached
Please answer fast
This is not a graded question
![[20] (1) GIVEN: The line, L, parameterized by the path c: R-R³, given by
=
(1,0, 4).
č(t) = (1 + 2t, 2 + t, 3+ 2t); and the point P
FIND: The distance from P to L, d(P, L).](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F4295bf62-da14-49f1-b3bf-6e678bc68de3%2F6a4f09c4-947b-496e-8276-0e75bb26caa4%2F4n6119c_processed.jpeg&w=3840&q=75)
Transcribed Image Text:[20] (1) GIVEN: The line, L, parameterized by the path c: R-R³, given by
=
(1,0, 4).
č(t) = (1 + 2t, 2 + t, 3+ 2t); and the point P
FIND: The distance from P to L, d(P, L).
![[10] (1)
GIVEN: L: c(t)
B = (0,1,2)
FIND: The distance from B to the line, L. d(B, L).
A
¯À = Ĉ(0)
&(B,L)
=
=
(-1+ 2t, 2-t, 3+t)
B
11
a
2(B,L)
= (-1,2,3)
4 + 1
+
b = AB
4 + 1 + 1
= (1,1,1)
7
â× b =
1161 sin d
=
= 121151α = (-2,-(1), 3)
sin
Mall
= 1 à x 511
lla
2 = √√√14
2
7
√√ = √21
1
3
1
-1
1 1
2.7
=√₁+ = √²/17
2.3](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F4295bf62-da14-49f1-b3bf-6e678bc68de3%2F6a4f09c4-947b-496e-8276-0e75bb26caa4%2Fv2828i9_processed.jpeg&w=3840&q=75)
Transcribed Image Text:[10] (1)
GIVEN: L: c(t)
B = (0,1,2)
FIND: The distance from B to the line, L. d(B, L).
A
¯À = Ĉ(0)
&(B,L)
=
=
(-1+ 2t, 2-t, 3+t)
B
11
a
2(B,L)
= (-1,2,3)
4 + 1
+
b = AB
4 + 1 + 1
= (1,1,1)
7
â× b =
1161 sin d
=
= 121151α = (-2,-(1), 3)
sin
Mall
= 1 à x 511
lla
2 = √√√14
2
7
√√ = √21
1
3
1
-1
1 1
2.7
=√₁+ = √²/17
2.3
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