Given the IP address 180.15.128.0/20. Now, using the given IP address space create five subnets in such a way so that less number of IP address is wasted for each subnet and the subnets will have the following number of hosts SubnetA - 23 hosts SubnetB - 50 hosts SubnetC - 2 hosts SubnetD - 6 hosts SubnetE - 10 hosts Now find out the following for each subnet: a) Network ID b) Broadcast address c) First usable IP address d) Last usable IP address e) Subnet mask Here, while solving the question make sure you are saving IP addresses. For example, SubnetA needs 23 hosts so in SubnetA you can allocate maximum 30 hosts. Follow the table for all the allowed number of hosts and required number of host bits for each subnet: Name of Subnet Maximum number hosts you can allocate Length of Host bits in the IP address cannot exceed SubnetA 30 5-bits SubnetB 62 6-bits SubnetC 2 2-bits SubnetD 6 3-bits SubnetE 14 4-bits
Given the IP address 180.15.128.0/20. Now, using the given IP address space create five subnets in such a way so that less number of IP address is wasted for each subnet and the subnets will have the following number of hosts
SubnetA - 23 hosts
SubnetB - 50 hosts
SubnetC - 2 hosts
SubnetD - 6 hosts
SubnetE - 10 hosts
Now find out the following for each subnet:
-
a) Network ID
-
b) Broadcast address
-
c) First usable IP address
-
d) Last usable IP address
-
e) Subnet mask
Here, while solving the question make sure you are saving IP addresses. For example, SubnetA needs 23 hosts so in SubnetA you can allocate maximum 30 hosts. Follow the table for all the allowed number of hosts and required number of host bits for each subnet:
|
Name of Subnet |
Maximum number hosts you can allocate |
Length of Host bits in the IP address cannot exceed |
|
SubnetA |
30 |
5-bits |
|
SubnetB |
62 |
6-bits |
|
SubnetC |
2 |
2-bits |
|
SubnetD |
6 |
3-bits |
|
SubnetE |
14 |
4-bits |
Trending now
This is a popular solution!
Step by step
Solved in 2 steps with 5 images
