Given the initial velocity as 19.44 m/s, can you perform/integrate the solution/function of acceleration and distance based on the typewritten formula / parts. Thank you
Given the initial velocity as 19.44 m/s, can you perform/integrate the solution/function of acceleration and distance based on the typewritten formula / parts. Thank you
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Given the initial velocity as 19.44 m/s, can you perform/integrate the solution/function of acceleration and distance based on the typewritten formula / parts. Thank you
Transcribed Image Text:Moreover, if the car is travelling at a higher speed of 70 km/hr under similar conditions,
where the deceleration of 4.63 m/s2 in 3 seconds is retained:
Vfinal
(Uinitial)? – 2(acceleration × distance)
-
(Uinitial)?
S =
2a
0.277778 m/s
(70 km/hrx-
S =
1 km/hr
2(4.63 m/s²)
S 40. 81 m
It can be observed that the distance value is already doubled when the initial velocity of
Transcribed Image Text:Part 3: In the case wherein a driver does not adhere the 3-second rule and is alternatively
maintaining a distance close enough for 1 second, the deceleration is resulted as:
dv
а —
dt
0- 50 km/hr
а —
1 hr
1s X
3600 s
(0.277778 m/s)²
1000 km/hr2
a = -180000 km/hr2 x
%3D
a x -13.89 m/s²
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