given the initial value problem x^(2)y'' + xy' + y = 0, y(1) = 2, y'(1) = 3 show that the two functions y1 = cos(lnx) and y2 = sin(lnx) are solutions of the differential equation x^(2)y'' + xy' + y = 0
given the initial value problem x^(2)y'' + xy' + y = 0, y(1) = 2, y'(1) = 3 show that the two functions y1 = cos(lnx) and y2 = sin(lnx) are solutions of the differential equation x^(2)y'' + xy' + y = 0
given the initial value problem x^(2)y'' + xy' + y = 0, y(1) = 2, y'(1) = 3 show that the two functions y1 = cos(lnx) and y2 = sin(lnx) are solutions of the differential equation x^(2)y'' + xy' + y = 0
show that the two functions y1 = cos(lnx) and y2 = sin(lnx) are solutions of the differential equation
x^(2)y'' + xy' + y = 0
With integration, one of the major concepts of calculus. Differentiation is the derivative or rate of change of a function with respect to the independent variable.
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