Given the information below, determine the lattice energy of MgCl2. Mg(s) → Mg(g) +122 kJ/mol DH°f = +147.1 kJ/mol ½ Cl2(g) → CI(g) DH2°f = Mg(g) - Mg (g) DH3°t = +738 kJ/mol kJ/mol Mg (g) Mg (g) DH4°f = +1450 Cl(g) - CI (g) DHs°f = -349 kJ/mol Mg(s) + Cl2(g) - MgCl2(s) DH6°r = -641 kJ/mol

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Chapter8: Bonding: General Concepts
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Problem 128AE: For each of the following, write an equation that corresponds to the energy given. a. lattice energy...
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9. Given the information below, determine the lattice energy of MgCl2.
Mg(s) - Mg(g)
DH°f = +147.1 kJ/mol
½ Cl2(g) – CI(g)
DH2°f =
+122 kJ/mol
Mg(g) – Mg*(g) DH3°t = +738 kJ/mol
Mg*(g)
Mg* (g)
DH4°F = +1450
kJ/mol
Cl(g) - Cl (g) DH5°f = -349 kJ/mol
Mg(s) + Cl2(g) – MgCl2(s) DH6°r = -641 kJ/mol
Transcribed Image Text:9. Given the information below, determine the lattice energy of MgCl2. Mg(s) - Mg(g) DH°f = +147.1 kJ/mol ½ Cl2(g) – CI(g) DH2°f = +122 kJ/mol Mg(g) – Mg*(g) DH3°t = +738 kJ/mol Mg*(g) Mg* (g) DH4°F = +1450 kJ/mol Cl(g) - Cl (g) DH5°f = -349 kJ/mol Mg(s) + Cl2(g) – MgCl2(s) DH6°r = -641 kJ/mol
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