GIVEN THE ILLUSTRATION BELOW. what could be the required magnitude of force F. given: resultant couple moment (on the frame) = 250 lb ft. clockwise.
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GIVEN THE ILLUSTRATION BELOW. what could be the required magnitude of force F.
given:
resultant couple moment (on the frame) = 250 lb ft. clockwise.
![-2 ft 2 ft-
F
B
] 30°
2 ft
150 Ib
150 lb
2 ft
30°7
F
2 ft](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F36e1da4c-fb1c-4601-8a9a-80fe67b00f18%2F66849312-dfb6-4eda-8b35-09967f1bba0f%2Fki1pubp_processed.jpeg&w=3840&q=75)
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- Masses M₁ M₂ M3 and om are connected together as shown in the figure below. 201 All the surfaces are smooth. If m 9 = 55°, calculate サー5m = 3.2kg, m₂ = 2.8kg, m3 = 3.8kg, 8m = 1.3kg and a) the acceleration of the system; b) the normal force between maand om.Need help solving the number of force in plane, centripetal force and if all forces are balanced.Needs Complete solution with 100 % accuracy.
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- A child spins a rock horizontally on string with speed v with radius rm = 0.25 kgr = 1.36 mT = .25 s Calculate the velocity v, acceleration a, and Net Force Fnet. List of known/unknown values, general equation used to solve (without numbers), algebra to rearrange the equation (without numbers), final answer with units.ha twodimensional tugotwar. Alex. Betty, and Charles pul horizontally on an automobile tire at the angles shown in the picture. The tire remains stationary in spite of the three puls Alex puls with force Fof magnitude 205 N. and Charles puls with force F cotmagritude 178 N. Note that the direction of F chnot given. What is the magritude of Bety's force FaCharles puls intal the direction drawninthe picture or the other possible directionfor equlibrium Number Units 0 Number UnitsRadius= 25 cm. Fig (a) If the stopper moves in a horizontal circle, but the string is not perpendicular to the pipe, can you figure out the radius? Fig (b) 25 cm Radius Analysis 1. Why does increasing the tension force decrease the period of revolution? 2. If the stopper moves as shown in the figure (b) above, is the centripetal force still equal to the tension force? Draw a free body diagram to help you see. Is it less than or more than the tension force?