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- Alice made a survey on the number of active Android applications her classmates have. The table summarizes the results. The Class Intervals contain the numbers of active Android Applications. The frequency is the number of students. Complete the table before answering the questions. Class Frequency Lower Class Boundary (LCB) Less than Cumulative Frequency (< cf) 50 Interval (1) 26-30 3 21-25 13 16-20 10 11-15 15 6-10 8 1-5 1 4129 47 34 1Suppose X - N (8, 2). Between what a values does 68.22% of the data lie? The range of x values is centered at the mean of the distribution (i.e., 8). Enter your answers in increasing order, to the nearest integer. 68.22% of the data lie between Number and NumberDetermine whether the statement is true or false. If it is false, rewrite it as a true statement. As the size of a sample increases, the mean of the distribution of sample means increases. Choose the correct answer below. O A. False. As the size of a sample increases, the mean of the distribution of sample means decreases. B. False. As the size of a sample increases, the mean of the distribution of sample means does not change. O C. True.
- In the given graph, What is the mean and standard deviation?The accompanying data represent the wait time (in minutes) for a random sample of 40 visitors to a popular attraction in a large amusement park. Use the sample data to complete parts (a) through (d). Click the icon to view the data for wait times. (a) Construct a relative frequency histogram of the data. Comment on the shape of the distribution. Choose the correct graph below. O A. ARelative Freq. 0.6- 0+ 60 Wait Time (min.) What is the shape of the distribution? O O E A. Q 60 B. No A. Yes, there is(are) B. A Relative Freq. 0.6 outlier(s). 07 0 60 Wait Time (min.) O A. The distribution is bell-shaped and roughly symmetric about its peak between 25 and 30 minutes. B. The distribution is right-skewed because the peak is between 0 and 5 minutes and the right tail is much longer than the left tail. C. The distribution is left-skewed because the peak is between 55 and 60 minutes and the left tail is much longer than the right tail. D. The distribution is right-skewed because the peak is…**PLEASE READ AND ACTUALLY ANSWER ALL QUESTIONS - THE LAST RESPONSE THIS QUESTION ANSWERED ONE OF FOUR. TOTAL CRAP** What is the income distribution of super shoppers? A supermarket super shopper is defined as a shopper for whom at least 70% of the items purchased were on sale or purchased with a coupon. In the following table, income units are in thousands of dollars, and each interval goes up to but does not include the given high value. The midpoints are given to the nearest thousand dollars. Income range 5-15 15-25 25-35 35-45 45-55 55 or more Midpoint x 10 20 30 40 50 60 Percent of super shoppers 22% 14% 20% 17% 19% 8% (a) Using the income midpoints x and the percent of super shoppers, do we have a valid probability distribution? Explain. Yes. The events are indistinct and the probabilities sum to less than 1.No. The events are indistinct and the probabilities sum to 1. No. The events are indistinct and the probabilities sum to more than 1.Yes. The events are…
- The median and mode of the wage distribution are known to be ₹ 3,350 and ₹ 3,400 respectively. Find the values of f3, f and f5 + No. of Employees Wages (in) 0-1,000 1,000-2,000 2,000-3,000 3,000-4,000 4 16 f3 f4 Wages (in) 4,000-5,000 5,000-6,000 6,000-7,000 Total No. of Employees f5 6 4 230The graph illustrates the distribution of test scores taken by College Algebra students. The maximum possible score on the test was 140, while the mean score was 73 and the standard deviation was 15. 38 73 Distribution of Test Scores 28 43 103 118 What is the approximate percentage of students who scored higher than 118 on the test? % What is the approximate percentage students who scored between 58 and 88 on the test? What is the approximate percentage of students who scored less than 43 on the test? What is the approximate percentage of students who scored between 73 and 88 on the test?answer please
- AsapThe temperatures in °C, at midday in a German city during summer of 2017, were mersured for eight days and the results are recorded below. 21, 12, 15, 12, 24, T, 30, 24 The mean temperature was found to be 21°C. (a) Find the value of T. (b) Write down the mode. (c) Find the median.The graph below displays a fire department's response Which interval contains the median response time? time, which measures the time from when the alarm is O 40-50 seconds sounded at the firehouse to the time the first fire engine leaves the station. 50-60 seconds 60–70 seconds Fire Department Response Times O 70-80 seconds 0.4 0.3 0.2 0.1 10 20 30 40 50 60 70 80 90 Response Time (Seconds). Relative Frequency