Given the function x(t)=t its Fourier transform, X(f) is: A. B. C. D. X(f)= sin(f) 2nf X(f) = j X(f) = j -∞ ≤ x < -1 −1≤x≤+1 cos(f) 2(π f)² cos(2л f) π f 1
Given the function x(t)=t its Fourier transform, X(f) is: A. B. C. D. X(f)= sin(f) 2nf X(f) = j X(f) = j -∞ ≤ x < -1 −1≤x≤+1 cos(f) 2(π f)² cos(2л f) π f 1
Introductory Circuit Analysis (13th Edition)
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ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
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![Given the function \( x(t) \):
\[
x(t) =
\begin{cases}
0 & , -\infty \leq x < -1 \\
t & , -1 \leq x \leq +1 \\
0 & , 1 < x < +\infty
\end{cases}
\]
its Fourier transform, \( X(f) \), is:
- **Option A:**
\[
X(f) = \frac{\sin(\pi f)}{2 \pi f} - \frac{\cos(\pi f)}{2(\pi f)^2}
\]
- **Option B (circled):**
\[
X(f) = j \frac{\cos(2 \pi f)}{\pi f} - j \frac{\sin(2 \pi f)}{2(\pi f)^2}
\]
- **Option C:**
\[
X(f) = j \frac{\sin(2 \pi f)}{2(2 \pi f)^2} - j \frac{\cos(2 \pi f)}{2 \pi f}
\]
- **Option D:**
\[
X(f) = \frac{1}{(\pi f)^2} \sin(\pi f) - \frac{1}{\pi f} \cos(\pi f)
\]
In the image, option B is highlighted with an oval, indicating it might be the correct Fourier transform for the given function \( x(t) \).](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fbfab9a7f-9ea4-456a-bb57-050ea1ff4d68%2F167e86fc-0287-43c5-b79a-a499e79af83b%2Fggpoo4s_processed.jpeg&w=3840&q=75)
Transcribed Image Text:Given the function \( x(t) \):
\[
x(t) =
\begin{cases}
0 & , -\infty \leq x < -1 \\
t & , -1 \leq x \leq +1 \\
0 & , 1 < x < +\infty
\end{cases}
\]
its Fourier transform, \( X(f) \), is:
- **Option A:**
\[
X(f) = \frac{\sin(\pi f)}{2 \pi f} - \frac{\cos(\pi f)}{2(\pi f)^2}
\]
- **Option B (circled):**
\[
X(f) = j \frac{\cos(2 \pi f)}{\pi f} - j \frac{\sin(2 \pi f)}{2(\pi f)^2}
\]
- **Option C:**
\[
X(f) = j \frac{\sin(2 \pi f)}{2(2 \pi f)^2} - j \frac{\cos(2 \pi f)}{2 \pi f}
\]
- **Option D:**
\[
X(f) = \frac{1}{(\pi f)^2} \sin(\pi f) - \frac{1}{\pi f} \cos(\pi f)
\]
In the image, option B is highlighted with an oval, indicating it might be the correct Fourier transform for the given function \( x(t) \).
Expert Solution
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Step 1: What is fourier transform
The Fourier transform is a mathematical tool used in signal processing, mathematics, physics, and engineering to analyze and represent a function in terms of its frequency components. It allows you to decompose a complex waveform into a sum of simple sinusoidal functions, each with a specific frequency, amplitude, and phase.
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