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Given the function g(x) 623 9x2 360z, find the first derivative, g' (x). %3D %3D = (2),6 Notice that g' (x) = 0 when z = - 4, that is, g'(-4) ='0. Now, we want to know whether there is a local minimum or local maximum at z = the second derivative test. -4, so we will use Find the second derivative, g''(x). (2),,6 Evaluate g''(- 4). g''(- 4) = %3D Based on the sign of this number, does this mean the graph of g(x) is concave up or concave doWn at - 4? -4 the graph of g(x) is Select an answer v o I = At z = %3D

Given the function g(x) 623 9x2 360z, find the first derivative, g' (x). %3D %3D = (2),6 Notice that g' (x) = 0 when z = - 4, that is, g'(-4) ='0. Now, we want to know whether there is a local minimum or local maximum at z = the second derivative test. -4, so we will use Find the second derivative, g''(x). (2),,6 Evaluate g''(- 4). g''(- 4) = %3D Based on the sign of this number, does this mean the graph of g(x) is concave up or concave doWn at - 4? -4 the graph of g(x) is Select an answer v o I = At z = %3D

Calculus: Early Transcendentals
Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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Given the function g(x) = 6x 9x 360x, find the first derivative, g'(x). %3D = (2),6 Notice that g' (x) = 0 when a = 4, that is, g'( – 4) ='0. - 4, so we will use Now, we want to know whether there is a local minimum or local maximum at x = the second derivative test. Find the second derivative, g''(x). (2),,6 Evaluate g''(- 4). g''(- 4) = Based on the sign of this number, does this mean the graph of g(x) is concave up or concave down at I = - 4? At x = - 4 the graph of g(x) is Select an answer v o - 4, does this mean that there is a local minimum or local Based on the concavity of g(x) at x = maximum at z = – 4? At z = - 4 there is a local Select an answer Question Help: D Video Submit Question Jump to Answer APR 1 étv 36,196 MacBook Pro 24
Transcribed Image Text:Given the function g(x) = 6x 9x 360x, find the first derivative, g'(x). %3D = (2),6 Notice that g' (x) = 0 when a = 4, that is, g'( – 4) ='0. - 4, so we will use Now, we want to know whether there is a local minimum or local maximum at x = the second derivative test. Find the second derivative, g''(x). (2),,6 Evaluate g''(- 4). g''(- 4) = Based on the sign of this number, does this mean the graph of g(x) is concave up or concave down at I = - 4? At x = - 4 the graph of g(x) is Select an answer v o - 4, does this mean that there is a local minimum or local Based on the concavity of g(x) at x = maximum at z = – 4? At z = - 4 there is a local Select an answer Question Help: D Video Submit Question Jump to Answer APR 1 étv 36,196 MacBook Pro 24
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