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Given the function f(x) = 4x3 sin(x) — 1, 0 ≤ x ≤ 2л has a solution a in the interval (0.7, 0.8) given in radians. An iterative formula, of the form given below, is used to find a. Xn+1 = A + B sin(xn), x1 = 0.75 where A and B are constants. a) Find out the values of A and B in terms of fractions. A = and B = b) Find the values of x2 and x3 correct to 4 decimal places. x2 = x3 =

Given the function f(x) = 4x3 sin(x) — 1, 0 ≤ x ≤ 2л has a solution a in the interval (0.7, 0.8) given in radians. An iterative formula, of the form given below, is used to find a. Xn+1 = A + B sin(xn), x1 = 0.75 where A and B are constants. a) Find out the values of A and B in terms of fractions. A = and B = b) Find the values of x2 and x3 correct to 4 decimal places. x2 = x3 =

Calculus: Early Transcendentals
Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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Given the function f(x) = 4x3 sin(x) — 1, 0 ≤ x ≤ 2л has a solution a in the interval (0.7, 0.8) given in radians. An iterative formula, of the form given below, is used to find a. Xn+1 = A + B sin(xn), x1 = 0.75 where A and B are constants. a) Find out the values of A and B in terms of fractions. A = and B = b) Find the values of x2 and x3 correct to 4 decimal places. x2 = x3 =
Transcribed Image Text:Given the function f(x) = 4x3 sin(x) — 1, 0 ≤ x ≤ 2л has a solution a in the interval (0.7, 0.8) given in radians. An iterative formula, of the form given below, is used to find a. Xn+1 = A + B sin(xn), x1 = 0.75 where A and B are constants. a) Find out the values of A and B in terms of fractions. A = and B = b) Find the values of x2 and x3 correct to 4 decimal places. x2 = x3 =
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