Given the function f(x) = 4x3 sin(x) — 1, 0 ≤ x ≤ 2л has a solution a in the interval (0.7, 0.8) given in radians. An iterative formula, of the form given below, is used to find a. Xn+1 = A + B sin(xn), x1 = 0.75 where A and B are constants. a) Find out the values of A and B in terms of fractions. A = and B = b) Find the values of x2 and x3 correct to 4 decimal places. x2 = x3 =
Given the function f(x) = 4x3 sin(x) — 1, 0 ≤ x ≤ 2л has a solution a in the interval (0.7, 0.8) given in radians. An iterative formula, of the form given below, is used to find a. Xn+1 = A + B sin(xn), x1 = 0.75 where A and B are constants. a) Find out the values of A and B in terms of fractions. A = and B = b) Find the values of x2 and x3 correct to 4 decimal places. x2 = x3 =
Algebra & Trigonometry with Analytic Geometry
13th Edition
ISBN:9781133382119
Author:Swokowski
Publisher:Swokowski
Chapter7: Analytic Trigonometry
Section7.6: The Inverse Trigonometric Functions
Problem 74E
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would greatly appreciate if you could solve this please
![Given the function
f(x) = 4x3 sin(x) — 1,
0 ≤ x ≤ 2л
has a solution a in the interval (0.7, 0.8) given in radians.
An iterative formula, of the form given below, is used to find a.
Xn+1 = A + B sin(xn), x1 = 0.75
where A and B are constants.
a) Find out the values of A and B in terms of fractions.
A =
and B =
b) Find the values of x2 and x3 correct to 4 decimal places.
x2 =
x3 =](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F5b435931-65a6-4d05-972c-a1ea4beea126%2F78c5de69-9bf6-44fc-a721-68844c10e46b%2Fayy5yc9_processed.png&w=3840&q=75)
Transcribed Image Text:Given the function
f(x) = 4x3 sin(x) — 1,
0 ≤ x ≤ 2л
has a solution a in the interval (0.7, 0.8) given in radians.
An iterative formula, of the form given below, is used to find a.
Xn+1 = A + B sin(xn), x1 = 0.75
where A and B are constants.
a) Find out the values of A and B in terms of fractions.
A =
and B =
b) Find the values of x2 and x3 correct to 4 decimal places.
x2 =
x3 =
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