Given the function f(x) = 4 + 5x, calculate the following values: f(a) = f(a + h) : f(a + h) – f(a) | h

Trigonometry (11th Edition)
11th Edition
ISBN:9780134217437
Author:Margaret L. Lial, John Hornsby, David I. Schneider, Callie Daniels
Publisher:Margaret L. Lial, John Hornsby, David I. Schneider, Callie Daniels
Chapter1: Trigonometric Functions
Section: Chapter Questions
Problem 1RE: 1. Give the measures of the complement and the supplement of an angle measuring 35°.
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## Derivative Calculations

Given the function \( f(x) = 4 + 5x^2 \), calculate the following values:

1. \( f(a) = \)
   - (Equation to find \( f(a) \), which represents the function evaluated at a point \( a \).)

2. \( f(a + h) = \)
   - (Equation to find \( f(a + h) \), which represents the function evaluated at \( a + h \), where \( h \) is a small increment.)

3. \(\frac{f(a + h) - f(a)}{h} = \)
   - (Expression to find the difference quotient, which is used to calculate the derivative of the function at point \( a \).)

**Explanation**:
- The function given is \( f(x) = 4 + 5x^2 \).
- To calculate \( f(a) \), you substitute \( a \) for \( x \) in the function.
- To calculate \( f(a + h) \), you substitute \( a + h \) for \( x \) in the function.
- To find the difference quotient, which approximates the derivative as \( h \) approaches 0, you use the expression \( \frac{f(a + h) - f(a)}{h} \).

### Sample Calculation Steps:

1. **Evaluate \( f(a) \)**:
   \[
   f(a) = 4 + 5a^2
   \]

2. **Evaluate \( f(a + h) \)**:
   \[
   f(a + h) = 4 + 5(a + h)^2
   \]
   Expand and simplify:
   \[
   f(a + h) = 4 + 5(a^2 + 2ah + h^2) = 4 + 5a^2 + 10ah + 5h^2
   \]

3. **Difference Quotient**:
   \[
   \frac{f(a + h) - f(a)}{h} = \frac{(4 + 5a^2 + 10ah + 5h^2) - (4 + 5a^2)}{h}
   \]
   Simplify:
   \[
   \frac{4 + 5a^2 + 10ah + 5h^2 -
Transcribed Image Text:## Derivative Calculations Given the function \( f(x) = 4 + 5x^2 \), calculate the following values: 1. \( f(a) = \) - (Equation to find \( f(a) \), which represents the function evaluated at a point \( a \).) 2. \( f(a + h) = \) - (Equation to find \( f(a + h) \), which represents the function evaluated at \( a + h \), where \( h \) is a small increment.) 3. \(\frac{f(a + h) - f(a)}{h} = \) - (Expression to find the difference quotient, which is used to calculate the derivative of the function at point \( a \).) **Explanation**: - The function given is \( f(x) = 4 + 5x^2 \). - To calculate \( f(a) \), you substitute \( a \) for \( x \) in the function. - To calculate \( f(a + h) \), you substitute \( a + h \) for \( x \) in the function. - To find the difference quotient, which approximates the derivative as \( h \) approaches 0, you use the expression \( \frac{f(a + h) - f(a)}{h} \). ### Sample Calculation Steps: 1. **Evaluate \( f(a) \)**: \[ f(a) = 4 + 5a^2 \] 2. **Evaluate \( f(a + h) \)**: \[ f(a + h) = 4 + 5(a + h)^2 \] Expand and simplify: \[ f(a + h) = 4 + 5(a^2 + 2ah + h^2) = 4 + 5a^2 + 10ah + 5h^2 \] 3. **Difference Quotient**: \[ \frac{f(a + h) - f(a)}{h} = \frac{(4 + 5a^2 + 10ah + 5h^2) - (4 + 5a^2)}{h} \] Simplify: \[ \frac{4 + 5a^2 + 10ah + 5h^2 -
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