Given: The four bar linkage is moving with WCD equal to 6 rad/s CCW. Find: The velocity of point E on link BC and angular velocity of link AB. Use ICR method. 30° B 0.3 m 0.3 m E WCD= 6 rad/s 0.6 m
Given: The four bar linkage is moving with WCD equal to 6 rad/s CCW. Find: The velocity of point E on link BC and angular velocity of link AB. Use ICR method. 30° B 0.3 m 0.3 m E WCD= 6 rad/s 0.6 m
Elements Of Electromagnetics
7th Edition
ISBN:9780190698614
Author:Sadiku, Matthew N. O.
Publisher:Sadiku, Matthew N. O.
ChapterMA: Math Assessment
Section: Chapter Questions
Problem 1.1MA
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Transcribed Image Text:**Problem Statement:**
Given: The four bar linkage is moving with \(\omega_{CD}\) equal to 6 rad/s CCW.
Find: The velocity of point E on link BC and the angular velocity of link AB. Use the ICR method.
**Diagram Explanation:**
The diagram illustrates a four-bar linkage consisting of links AB, BC, and CD. The linkage is in motion, and the angular velocity \(\omega_{CD}\) is 6 rad/s counterclockwise (CCW).
**Key Measurements:**
- Link CD is vertical and has a length of 0.6 m.
- Link BC is horizontal, with sections labeled:
- From B to E: 0.3 m
- From E to C: 0.3 m
- Link AB makes a 30° angle with the horizontal ground.
**Objective:**
- Determine the velocity of point E on link BC.
- Calculate the angular velocity of link AB using the Instantaneous Center of Rotation (ICR) method.
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