Given the following two half-reactions, write the overall reaction in the direction in which it is product-favored, and calculate the standard cell potential. Pb2+(aq) + 2 e– → Pb(s) E° = –0.126 V Fe3+(aq) + e– → Fe2+(s) E° = +0.771 V Choose the correct answer a. Pb2+(aq) + Fe2+(s) → Pb(s) + Fe3+(aq); = +0.645 V b. Pb(s) + 2 Fe3+(aq) → Pb2+(aq) + 2 Fe2+(s); = +1.416 V c. Pb(s) + 2 Fe3+(aq) → Pb2+(aq) + 2 Fe2+(s); = +0.897 V d. Pb(s) + Fe3+(aq) → Pb2+(aq) + Fe2+(s); = +0.645 V e. Pb2+(aq) + 2 Fe2+(s) → Pb(s) + 2 Fe3+(aq); = +0.897 V
Given the following two half-reactions, write the overall reaction in the direction in which it is product-favored, and calculate the standard cell potential. Pb2+(aq) + 2 e– → Pb(s) E° = –0.126 V Fe3+(aq) + e– → Fe2+(s) E° = +0.771 V Choose the correct answer a. Pb2+(aq) + Fe2+(s) → Pb(s) + Fe3+(aq); = +0.645 V b. Pb(s) + 2 Fe3+(aq) → Pb2+(aq) + 2 Fe2+(s); = +1.416 V c. Pb(s) + 2 Fe3+(aq) → Pb2+(aq) + 2 Fe2+(s); = +0.897 V d. Pb(s) + Fe3+(aq) → Pb2+(aq) + Fe2+(s); = +0.645 V e. Pb2+(aq) + 2 Fe2+(s) → Pb(s) + 2 Fe3+(aq); = +0.897 V
Chemistry
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Chapter1: Chemical Foundations
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Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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Given the following two half-reactions, write the overall reaction in the direction in which it is product-favored, and calculate the standard cell potential.
|
|
Pb2+(aq) + 2 e– → Pb(s) |
E° = –0.126 V |
|
|
Fe3+(aq) + e– → Fe2+(s) |
E° = +0.771 V |
Choose the correct answer
a. Pb2+(aq) + Fe2+(s) → Pb(s) + Fe3+(aq); = +0.645 V
b. Pb(s) + 2 Fe3+(aq) → Pb2+(aq) + 2 Fe2+(s); = +1.416 V
c. Pb(s) + 2 Fe3+(aq) → Pb2+(aq) + 2 Fe2+(s); = +0.897 V
d. Pb(s) + Fe3+(aq) → Pb2+(aq) + Fe2+(s); = +0.645 V
e. Pb2+(aq) + 2 Fe2+(s) → Pb(s) + 2 Fe3+(aq); = +0.897 V
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