Given the following two alternatives and using the repeatability assumption and MARR=15%/year, the equation for computing the present worth of vendor B is Vendor A First Cost, $ -15,000 Annual cost, $ per year -3500 Salvage Value, $ 1000 Life, years 3 Vendor B -18000 -3100 2000 4 O PW=18000-18000(P/F, 15%, 4) -18000 (P/F,15%, 8) +2000(P/F, 15%, 4)+2000(P/F, 15%, 8) +2000(P/F, 15%, 12)-3100(P/A, 15%, 12) O PW=18000-18000(P/F, 15%, 12) +2000(P/F, 15%, 4)+2000(P/F, 15%, 8)+2000(P/F, 15%, 12)-3100 (P/A, 15%, 12) O PW=-18000-18000(P/F,15%, 4) -18000 (P/F, 15%, 8) +2000(P/F, 15%, 4)+2000(P/F, 15%, 8)+2000(P/F, 15%, 12)-3100(P/A, 15%, 12) O PW=-18000(P/F,15%, 4) -18000(P/F,15%, 8)+2000(P/F, 15%, 4) +2000(P/F, 15%, 8) +2000(P/F, 15%, 12)-3100(P/A, 15%, 12)
Given the following two alternatives and using the repeatability assumption and MARR=15%/year, the equation for computing the present worth of vendor B is Vendor A First Cost, $ -15,000 Annual cost, $ per year -3500 Salvage Value, $ 1000 Life, years 3 Vendor B -18000 -3100 2000 4 O PW=18000-18000(P/F, 15%, 4) -18000 (P/F,15%, 8) +2000(P/F, 15%, 4)+2000(P/F, 15%, 8) +2000(P/F, 15%, 12)-3100(P/A, 15%, 12) O PW=18000-18000(P/F, 15%, 12) +2000(P/F, 15%, 4)+2000(P/F, 15%, 8)+2000(P/F, 15%, 12)-3100 (P/A, 15%, 12) O PW=-18000-18000(P/F,15%, 4) -18000 (P/F, 15%, 8) +2000(P/F, 15%, 4)+2000(P/F, 15%, 8)+2000(P/F, 15%, 12)-3100(P/A, 15%, 12) O PW=-18000(P/F,15%, 4) -18000(P/F,15%, 8)+2000(P/F, 15%, 4) +2000(P/F, 15%, 8) +2000(P/F, 15%, 12)-3100(P/A, 15%, 12)
Chapter1: Making Economics Decisions
Section: Chapter Questions
Problem 1QTC
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
Transcribed Image Text:Given the following two alternatives and using the repeatability
assumption and MARR=15%/year, the equation for computing the
present worth of vendor B is
Vendor A
First Cost, $
-15,000
Annual cost, $ per year -3500
Salvage Value, $
1000
Life, years
3
Vendor B
-18000
-3100
2000
4
OPW=18000-18000(P/F,15%, 4)-18000(P/F,15%, 8)+2000(P/F, 15%,
4)+2000(P/F, 15%, 8) +2000 (P/F, 15%, 12)-3100(P/A, 15%, 12)
PW=18000-18000(P/F, 15%, 12)+2000(P/F, 15%, 4)+2000 (P/F, 15%,
8)+2000(P/F, 15%, 12)-3100(P/A, 15%, 12)
O PW=-18000-18000(P/F,15%, 4) - 18000(P/F,15%, 8) +2000(P/F, 15%,
4)+2000(P/F, 15%, 8) +2000 (P/F, 15%, 12)-3100(P/A, 15%, 12)
O PW=-18000(P/F,15%, 4) -18000(P/F,15%, 8) +2000(P/F, 15%, 4)+2000(P/F,
15%, 8) +2000(P/F, 15%, 12)-3100(P/A, 15%, 12)
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