Given the following three vectors: Show that v1, v2, iz form a basis of R by proving that they are independent AND Span {di, ö2, üz} = R*. To justify Span {v1, d2, vz} = R°, show that for a random vector y e R°, ye Span {v1, 02, 03} , or = a•-0j+ß-7z+y•7g, a, ß, y E R
Given the following three vectors: Show that v1, v2, iz form a basis of R by proving that they are independent AND Span {di, ö2, üz} = R*. To justify Span {v1, d2, vz} = R°, show that for a random vector y e R°, ye Span {v1, 02, 03} , or = a•-0j+ß-7z+y•7g, a, ß, y E R
Algebra and Trigonometry (6th Edition)
6th Edition
ISBN:9780134463216
Author:Robert F. Blitzer
Publisher:Robert F. Blitzer
ChapterP: Prerequisites: Fundamental Concepts Of Algebra
Section: Chapter Questions
Problem 1MCCP: In Exercises 1-25, simplify the given expression or perform the indicated operation (and simplify,...
Related questions
Question
Show that u1, u2, u3 form a basis of R3 by proving that they are independent and Span{u1, u2, u3}= R3.
![Given the following three vectors:
\[
\mathbf{v}_1 = \begin{bmatrix} 1 \\ 0 \\ -1 \end{bmatrix}, \quad \mathbf{v}_2 = \begin{bmatrix} 0 \\ -1 \\ 1 \end{bmatrix}, \quad \mathbf{v}_3 = \begin{bmatrix} 1 \\ 0 \\ 1 \end{bmatrix}
\]
Show that \(\mathbf{v}_1, \mathbf{v}_2, \mathbf{v}_3\) form a basis of \(\mathbb{R}^3\) by proving that they are independent and \(\text{Span}\{\mathbf{v}_1, \mathbf{v}_2, \mathbf{v}_3\} = \mathbb{R}^3\).
To justify \(\text{Span}\{\mathbf{v}_1, \mathbf{v}_2, \mathbf{v}_3\} = \mathbb{R}^3\), show that for a random vector:
\[
\mathbf{y} = \begin{bmatrix} a \\ b \\ c \end{bmatrix} \in \mathbb{R}^3, \quad \mathbf{y} \in \text{Span}\{\mathbf{v}_1, \mathbf{v}_2, \mathbf{v}_3\}, \, \text{or} \, \begin{bmatrix} a \\ b \\ c \end{bmatrix} = \alpha \mathbf{v}_1 + \beta \mathbf{v}_2 + \gamma \mathbf{v}_3, \, \alpha, \beta, \gamma \in \mathbb{R}
\]](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Ff90e9f76-a8ee-4e86-857e-4cb9f0bb2381%2F559feb33-5439-4f6f-8e73-37c68b935665%2F5bjnv8p_processed.png&w=3840&q=75)
Transcribed Image Text:Given the following three vectors:
\[
\mathbf{v}_1 = \begin{bmatrix} 1 \\ 0 \\ -1 \end{bmatrix}, \quad \mathbf{v}_2 = \begin{bmatrix} 0 \\ -1 \\ 1 \end{bmatrix}, \quad \mathbf{v}_3 = \begin{bmatrix} 1 \\ 0 \\ 1 \end{bmatrix}
\]
Show that \(\mathbf{v}_1, \mathbf{v}_2, \mathbf{v}_3\) form a basis of \(\mathbb{R}^3\) by proving that they are independent and \(\text{Span}\{\mathbf{v}_1, \mathbf{v}_2, \mathbf{v}_3\} = \mathbb{R}^3\).
To justify \(\text{Span}\{\mathbf{v}_1, \mathbf{v}_2, \mathbf{v}_3\} = \mathbb{R}^3\), show that for a random vector:
\[
\mathbf{y} = \begin{bmatrix} a \\ b \\ c \end{bmatrix} \in \mathbb{R}^3, \quad \mathbf{y} \in \text{Span}\{\mathbf{v}_1, \mathbf{v}_2, \mathbf{v}_3\}, \, \text{or} \, \begin{bmatrix} a \\ b \\ c \end{bmatrix} = \alpha \mathbf{v}_1 + \beta \mathbf{v}_2 + \gamma \mathbf{v}_3, \, \alpha, \beta, \gamma \in \mathbb{R}
\]
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