Given the following thermochemical equations,Equation 1: 4B(s) + 3O2(g) → 2B2O3(s) ∆Ho= -2543.8 kJEquation 2: H2 (g) + ½ O2(g) → H2O (g) ∆Ho= -241.8 kJEquation 3: B2H6(s) + 3O2(g) → B2O3(s) + 3H2O (g) ∆Ho= -2032.9 kJWhich of the following statement/s is/are true in calculating the ∆Ho for the decomposition of B2H6 into its elements? Check all that apply. Equation 1 was reversed and divided by 1/2. Equation 2 was reversed and multiplied by 3. Equation 1 was reveresed and divided by 2. Equation 3 was neither reversed nor multiplied by a factor.

Answered: Given the following thermochemical…

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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Given the following thermochemical equations,

Equation 1:     4B(s) + 3O₂(g) → 2B₂O₃(s)                         ∆H^o= -2543.8 kJ
Equation 2:     H₂ (g) + ½ O₂(g) → H₂O (g)                        ∆H^o= -241.8 kJ
Equation 3:     B₂H₆(s) + 3O₂(g) → B₂O₃(s) + 3H₂O (g)   ∆H^o= -2032.9 kJ

Which of the following statement/s is/are true in calculating the ∆H^o for the decomposition of B₂H₆ into its elements? Check all that apply.

		Equation 1 was reversed and divided by 1/2.
		Equation 2 was reversed and multiplied by 3.
		Equation 1 was reveresed and divided by 2.
		Equation 3 was neither reversed nor multiplied by a factor.

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