Given the following statement: 6 * (8-3) Make the Annotated Parse Tree based on the translation scheme below. S→ B {A.i = B.val} A {S.val = A.s} A → - B {A1.i = A.i - B.val} A1 {A.s = A1.s} A → {A.s = A.i} B → D {C.i = D.val} C {B.val = C.s} C+ * D {C1.i = C.i * D.val} C1 {C.s = C1.s} C > {C.s = C.i} D → (S){D.val = S.val} D → num {D.val = num.val} %3D %3D %3D %3D %3D
Given the following statement: 6 * (8-3) Make the Annotated Parse Tree based on the translation scheme below. S→ B {A.i = B.val} A {S.val = A.s} A → - B {A1.i = A.i - B.val} A1 {A.s = A1.s} A → {A.s = A.i} B → D {C.i = D.val} C {B.val = C.s} C+ * D {C1.i = C.i * D.val} C1 {C.s = C1.s} C > {C.s = C.i} D → (S){D.val = S.val} D → num {D.val = num.val} %3D %3D %3D %3D %3D
Computer Networking: A Top-Down Approach (7th Edition)
7th Edition
ISBN:9780133594140
Author:James Kurose, Keith Ross
Publisher:James Kurose, Keith Ross
Chapter1: Computer Networks And The Internet
Section: Chapter Questions
Problem R1RQ: What is the difference between a host and an end system? List several different types of end...
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Question
Computer science
![Given the following statement: 6 * (8-3)
Make the Annotated Parse Tree based on
the translation scheme below.
S → B {A.i = B.val} A {S.val = A.s}
A → - B {A1.i = A.i - B.val} A1 {A.s = A1.s}
A → {A.s = A.i}
B → D {C.i = D.val} C {B.val = C.s}
C → * D {C1.i = C.i * D.val} C1 {C.s = C1.s}
C - {C.s = C.i}
D → (S){D.val = S.val}
D → num {D.val = num.val}
%3D
%3D
%3D
%3D](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fe4d3483d-c369-4307-b9c1-b011f793a1d2%2Fddeadcec-7bdc-4fb5-b270-8c11effef301%2Fc8x3px_processed.jpeg&w=3840&q=75)
Transcribed Image Text:Given the following statement: 6 * (8-3)
Make the Annotated Parse Tree based on
the translation scheme below.
S → B {A.i = B.val} A {S.val = A.s}
A → - B {A1.i = A.i - B.val} A1 {A.s = A1.s}
A → {A.s = A.i}
B → D {C.i = D.val} C {B.val = C.s}
C → * D {C1.i = C.i * D.val} C1 {C.s = C1.s}
C - {C.s = C.i}
D → (S){D.val = S.val}
D → num {D.val = num.val}
%3D
%3D
%3D
%3D
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