Given the following situation The value of a car decreases by 5t2 % per year. Set up the Differential Equation that models this situation. A AP %3D – 0.05 V dt (B AP = 0.05 V dt AP dt - 0.05 12 v (D = 5 12 AP dt AP - 5 1² E dt dV = 0.05 t2 V dt F

Q: 3. √11

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