Given the following sampling distribution: What is P(X > -9)? X -16 -9 -5 P(X)/100/50 7/100/100 8 17

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Solve the following

Given the following sampling distribution:

\[
\begin{array}{|c|c|c|c|c|c|}
\hline
X & -16 & -9 & -5 & 8 & 17 \\
\hline
P(X) & \frac{1}{100} & \frac{3}{50} & \frac{7}{100} & \frac{7}{100} & \\
\hline
\end{array}
\]

What is P(X > -9)?

**Explanation:**

This table represents a probability distribution, where:

- \( X \) denotes the value of the random variable.
- \( P(X) \) represents the probability of each value of \( X \).

To find \( P(X > -9) \), sum the probabilities of the values where \( X \) is greater than -9, which are -5, 8, and 17:

\[ P(X > -9) = P(X = -5) + P(X = 8) + P(X = 17) \]

Substitute the corresponding probabilities:

\[ P(X > -9) = \frac{7}{100} + \frac{7}{100} + P(X = 17) \]

Since \( P(X) \) for 17 is not given, ensure to check additional data or context to complete the calculation.
Transcribed Image Text:Given the following sampling distribution: \[ \begin{array}{|c|c|c|c|c|c|} \hline X & -16 & -9 & -5 & 8 & 17 \\ \hline P(X) & \frac{1}{100} & \frac{3}{50} & \frac{7}{100} & \frac{7}{100} & \\ \hline \end{array} \] What is P(X > -9)? **Explanation:** This table represents a probability distribution, where: - \( X \) denotes the value of the random variable. - \( P(X) \) represents the probability of each value of \( X \). To find \( P(X > -9) \), sum the probabilities of the values where \( X \) is greater than -9, which are -5, 8, and 17: \[ P(X > -9) = P(X = -5) + P(X = 8) + P(X = 17) \] Substitute the corresponding probabilities: \[ P(X > -9) = \frac{7}{100} + \frac{7}{100} + P(X = 17) \] Since \( P(X) \) for 17 is not given, ensure to check additional data or context to complete the calculation.
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