Given the following reaction: 2C₂H₂(g) +50₂(g) → 4CO₂(g) + 2H₂O(g) AH = -2511.6 kJ What is the energy change when 2.26 g of C₂H₂ react with excess O₂?
Thermochemistry
Thermochemistry can be considered as a branch of thermodynamics that deals with the connections between warmth, work, and various types of energy, formed because of different synthetic and actual cycles. Thermochemistry describes the energy changes that occur as a result of reactions or chemical changes in a substance.
Exergonic Reaction
The term exergonic is derived from the Greek word in which ‘ergon’ means work and exergonic means ‘work outside’. Exergonic reactions releases work energy. Exergonic reactions are different from exothermic reactions, the one that releases only heat energy during the course of the reaction. So, exothermic reaction is one type of exergonic reaction. Exergonic reaction releases work energy in different forms like heat, light or sound. For example, a glow stick releases light making that an exergonic reaction and not an exothermic reaction since no heat is released. Even endothermic reactions at very high temperature are exergonic.
![**Chemical Reaction and Energy Change Calculation**
**Question:**
Given the following reaction:
\[ 2 \text{C}_2\text{H}_2(\text{g}) + 5 \text{O}_2(\text{g}) \rightarrow 4 \text{CO}_2(\text{g}) + 2 \text{H}_2\text{O}(\text{g}) \]
\[ \Delta H = -2511.6 \, \text{kJ} \]
What is the energy change when 2.26 g of \(\text{C}_2\text{H}_2\) react with excess \(\text{O}_2\)?
**Input Method:**
Use the numeric keypad to enter the calculated energy change in kJ. There is also an option to clear your input or multiply by powers of ten if needed.
**Note:**
To find the energy change, calculate the moles of \(\text{C}_2\text{H}_2\) using its molar mass, then use the stoichiometry of the reaction to find the energy change based on the given \(\Delta H\).](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fdbde2dde-363b-4b24-a6fb-483d1b19c687%2F273d028c-e2d6-4f67-8380-27243517b77b%2F4vrdqip_processed.jpeg&w=3840&q=75)
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