Given the following processes and needed burst time for each oneProcess Burst Time Arrival timeP1131P28Using Round Robin scheduling (with a quantum of 5), the waiting times of each process are:P1 =%3DP2 =

ROUND ROBIN SCHEDULING: PROCESS BURST TIME ARRIVAL TIME WAITING TIME P1 13 1 P2 8 0…

Answered: Given the following processes and…

Given the following processes and needed burst time for each one Process Burst Time Arrival time P1 13 P2 Using Round Robin scheduling (with a quantum of 5), the waiting times of each process are:

Database System Concepts

7th Edition

ISBN:9780078022159

Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Chapter1: Introduction

Section: Chapter Questions

Problem 1PE

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Q-1: Draw the Shortest Remaining Time First (with Preemption) and Round Robin (no Preemption) Gannt chart for the following processes. Calculate average wait time for each algorithm using the processes data below. Round Robin uses a time quanta of 3. Process Number PO P1 P2 P3 P4 P5 Arrival Time Burst Time to Complete 10 2 0 3 4 13 25 26 6 10 1 3
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You are designing a real-time system that must execute the following set of processes: P1(20,3); P2(5,2); P3(350,15); P4(500,22); P5(100,10) Note: The first parameter listed for each process is the period, and the second is the maximum execution time. Can these processes be scheduled using Rate Monotonic? You must justify your answer. Can these processes be scheduled using Earliest Deadline First? You must justify your answer. If possible, identify the simplest of these strategies that can be used to schedule these processes.
a. Three processes share four resource units that can be reserved and released only one at a time. Each process needs a maximum of two units. Show that a deadlock cannot occur. b. N processes share M resource units that can be reserved and released only one at a time. The maximum need of each process does not exceed M, and the sum of all maximum needs is less than M + N. Show that a deadlock cannot occur.
a. Three processes share four resource units that can be reserved and released only one at a time. Each process needs a maximum of two units. Show that a deadlock cannot occur. b. N processes share M resource units that can be reserved and released only one at a time. The maximum need of each process does not exceed M, and the sum of all maximum needs is less than M + N. Show that a deadlock cannot occur.
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Consider the following set of processes, with the length of the CPU burst given in milliseconds: Process P1 P2 P3 P4 P5 Burst Time 5 3 1 7 4 Priority 4 1 2 2 3 The processes are assumed to have arrived in the order P1, P2, P3, P4, P5, all at time 0. b) What is the turnaround time of each process for each of the scheduling algorithms in part a? c) What is the waiting time of each process for each of these scheduling algorithms?
a. Three processes share four resource units that can be reserved and released only one at a time. Each process needs a maximum of two units. Show that a deadlock cannot occur. b. N processes share M resource units that can be reserved and released only one at a time. The maximum need of each process does not exceed M, and the sum of all maximum needs is less than M + N. Show that a deadlock cannot occur.
Three periodic processes of an operating system has P(burst time, period) as follows: P1(4,20), P2(6,10), P3(12,30). Which of the following is true when these processes are scheduled with Rate-Monotonic scheduling algorithm that assigns priorities proportional to periods (shorter period has higher priority). a)No process misses a deadline b)Only P3 misses its deadline c)P1, P2 and P3 all miss their deadlines d)P2 and P3 both miss their deadlines
a. Three processes share four resource units that can be reserved and released only one at a time. Each process needs a maximum of two units. Show that a deadlock cannot occur. b. N processes share M resource units that can be reserved and released only one at a time. The maximum need of each process does not exceed M, and the sum of all maximum needs is less than M + N. Show that a deadlock cannot occur.