Given the following nuclear reaction: 22 Ra→He + 4X 88 Column A → N 2. m 3. What is the atomic mass of the new atom? What is the atomic number of the new atom? What is the symbol of the new atom? What type of decay is demonstrated here? Column B a. 88 b. 224 c. 90 d. 228 2. Rn f. Alpha Decay g. Gamma Decay 1. 220 J. 86 k. Beta Decay 1. 84 m. Ra
Given the following nuclear reaction: 22 Ra→He + 4X 88 Column A → N 2. m 3. What is the atomic mass of the new atom? What is the atomic number of the new atom? What is the symbol of the new atom? What type of decay is demonstrated here? Column B a. 88 b. 224 c. 90 d. 228 2. Rn f. Alpha Decay g. Gamma Decay 1. 220 J. 86 k. Beta Decay 1. 84 m. Ra
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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Showing the following nuclear reaction
![### Understanding Alpha Decay through Nuclear Reactions
**Given the Following Nuclear Reaction:**
\[ \text{ }^{224}_{88}\text{Ra} \rightarrow \text{ }^{4}_{2}\text{He} + \text{ }^{A}_{Z}\text{X} \]
**Match the Items in Column A to Column B**
**Column A**
1. What is the atomic mass of the new atom?
2. What is the atomic number of the new atom?
3. What is the symbol of the new atom?
4. What type of decay is demonstrated here?
**Column B**
a. 88
b. 224
c. 90
d. 228
e. Rn
f. Alpha Decay
g. Gamma Decay
h. Th
i. 220
j. 86
k. Beta Decay
l. 84
m. Ra
**Explanation of the Nuclear Reaction:**
In the given nuclear reaction, \(\text{ }^{224}_{88}\text{Ra}\) indicates Radium with an atomic mass of 224 and an atomic number of 88. During the reaction, Radium undergoes alpha decay, emitting an alpha particle (\(\text{ }^{4}_{2}\text{He}\)) and forming a new atom (\(\text{ }^{A}_{Z}\text{X}\)).
**Matching Items:**
1. The atomic mass of the new atom: \(\text{ }^{224}_{88}\text{Ra} \rightarrow \text{ }^{4}_{2}\text{He} + \text{ }^{A}_{Z}\text{X}\)
The new atom's mass number is: 224 (Ra's atomic mass) - 4 (alpha particle mass) = 220.
Answer: **i. 220**
2. The atomic number of the new atom: \(\text{ }^{224}_{88}\text{Ra} \rightarrow \text{ }^{4}_{2}\text{He} + \text{ }^{A}_{Z}\text{X}\)
The new atom's atomic number is: 88 (Ra's atomic number) - 2 (alpha particle number) = 86.
Answer: **j. 86**
3. The symbol of the new atom can be determined using the atomic number 86, which corresponds](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F4ad80e50-c954-4544-ab96-d220f1f8ae54%2F6eb6b59f-e14f-4426-a8fc-3d1b3712de3d%2Fwir6l34_processed.jpeg&w=3840&q=75)
Transcribed Image Text:### Understanding Alpha Decay through Nuclear Reactions
**Given the Following Nuclear Reaction:**
\[ \text{ }^{224}_{88}\text{Ra} \rightarrow \text{ }^{4}_{2}\text{He} + \text{ }^{A}_{Z}\text{X} \]
**Match the Items in Column A to Column B**
**Column A**
1. What is the atomic mass of the new atom?
2. What is the atomic number of the new atom?
3. What is the symbol of the new atom?
4. What type of decay is demonstrated here?
**Column B**
a. 88
b. 224
c. 90
d. 228
e. Rn
f. Alpha Decay
g. Gamma Decay
h. Th
i. 220
j. 86
k. Beta Decay
l. 84
m. Ra
**Explanation of the Nuclear Reaction:**
In the given nuclear reaction, \(\text{ }^{224}_{88}\text{Ra}\) indicates Radium with an atomic mass of 224 and an atomic number of 88. During the reaction, Radium undergoes alpha decay, emitting an alpha particle (\(\text{ }^{4}_{2}\text{He}\)) and forming a new atom (\(\text{ }^{A}_{Z}\text{X}\)).
**Matching Items:**
1. The atomic mass of the new atom: \(\text{ }^{224}_{88}\text{Ra} \rightarrow \text{ }^{4}_{2}\text{He} + \text{ }^{A}_{Z}\text{X}\)
The new atom's mass number is: 224 (Ra's atomic mass) - 4 (alpha particle mass) = 220.
Answer: **i. 220**
2. The atomic number of the new atom: \(\text{ }^{224}_{88}\text{Ra} \rightarrow \text{ }^{4}_{2}\text{He} + \text{ }^{A}_{Z}\text{X}\)
The new atom's atomic number is: 88 (Ra's atomic number) - 2 (alpha particle number) = 86.
Answer: **j. 86**
3. The symbol of the new atom can be determined using the atomic number 86, which corresponds
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