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Given the following instruction stored at address 8 in memory: PC/Address 8 Instruction BEQ R5, R6, 0xC ssume register 5 contains OxACAB, and register 6 contains OxACAB and that the offset is presented as a exadecimal digit which represents a signed, 4-bit, two's complement value. fter this instruction is executed, what will be the address of the next instruction? Explain how you calculated our answer.

Given the following instruction stored at address 8 in memory: PC/Address 8 Instruction BEQ R5, R6, 0xC ssume register 5 contains OxACAB, and register 6 contains OxACAB and that the offset is presented as a exadecimal digit which represents a signed, 4-bit, two's complement value. fter this instruction is executed, what will be the address of the next instruction? Explain how you calculated our answer.

Computer Networking: A Top-Down Approach (7th Edition)
Computer Networking: A Top-Down Approach (7th Edition)
7th Edition
ISBN:9780133594140
Author:James Kurose, Keith Ross
Publisher:James Kurose, Keith Ross
Chapter1: Computer Networks And The Internet
Section: Chapter Questions
Problem R1RQ: What is the difference between a host and an end system? List several different types of end...
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**Instruction Details:** Given the following instruction stored at address 8 in memory: - **PC/Address**: 8 - **Instruction**: BEQ R5, R6, 0xC Assume register 5 contains 0xACAB, and register 6 contains 0xACAB, and that the offset is presented as a hexadecimal digit, which represents a signed, 4-bit, two’s complement value. **Question:** After this instruction is executed, what will be the address of the next instruction? Explain how you calculated your answer. **Explanation:** 1. **Instruction Type**: BEQ (Branch if Equal). 2. **Comparison**: Compare the contents of R5 and R6. Since both contain 0xACAB, they are equal. 3. **Offset Calculation**: 0xC in a signed, 4-bit two’s complement representation is 1100 in binary, which is +12 in decimal. 4. **Next Address Calculation**: - Current address: 8 - Add offset (+12): 8 + 12 = 20 Therefore, the next instruction will be executed at address 20, assuming the branch is taken because the values in R5 and R6 are equal.
Transcribed Image Text:**Instruction Details:** Given the following instruction stored at address 8 in memory: - **PC/Address**: 8 - **Instruction**: BEQ R5, R6, 0xC Assume register 5 contains 0xACAB, and register 6 contains 0xACAB, and that the offset is presented as a hexadecimal digit, which represents a signed, 4-bit, two’s complement value. **Question:** After this instruction is executed, what will be the address of the next instruction? Explain how you calculated your answer. **Explanation:** 1. **Instruction Type**: BEQ (Branch if Equal). 2. **Comparison**: Compare the contents of R5 and R6. Since both contain 0xACAB, they are equal. 3. **Offset Calculation**: 0xC in a signed, 4-bit two’s complement representation is 1100 in binary, which is +12 in decimal. 4. **Next Address Calculation**: - Current address: 8 - Add offset (+12): 8 + 12 = 20 Therefore, the next instruction will be executed at address 20, assuming the branch is taken because the values in R5 and R6 are equal.
**Question:** What will be the address of the next instruction if the following is executed? **PC/Address:** A **Instruction:** JMP 4 --- The question asks what the next instruction's address will be when a jump instruction (JMP) with an operand of 4 is executed from the current address labeled as "A". In assembly language, the JMP instruction causes the program to jump to a specific address in memory. Here, the jump is relative to the current position, moving forward by 4 addresses from the current one.
Transcribed Image Text:**Question:** What will be the address of the next instruction if the following is executed? **PC/Address:** A **Instruction:** JMP 4 --- The question asks what the next instruction's address will be when a jump instruction (JMP) with an operand of 4 is executed from the current address labeled as "A". In assembly language, the JMP instruction causes the program to jump to a specific address in memory. Here, the jump is relative to the current position, moving forward by 4 addresses from the current one.
Expert Solution
Step 1: Some Overviews

Let's start by understanding the instruction "BEQ R5, R6, 0xC". This is a branch instruction that stands for "Branch if Equal." It checks if the values in registers R5 and R6 are equal. If they are, it branches to the target address, which is the sum of the current program counter (PC) and the sign-extended immediate value.

In this case, register 5 (R5) contains the value 0xACAB, register 6 (R6) also contains the value 0xACAB, and the immediate value is 0xC. The immediate value is a 4-bit two's complement representation, so 0xC is equivalent to 12 in decimal.


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