Given the following information for a simple spiraled curve: o = 38°00'00" o Da = 4°30'00" • Ls = 800 feet o T.S.Sta 35+00 What is the stationing of the C.S.? O 43+44.44 43+00.00 O None of the above O 43+47.52 35+44.44

Q: Item 1 A-2.5% grade meets a +2.50% grade at station 4 + 200 and elevation 146.657 m, 180-m curve,…

A:

Q: A-2.5% grade meets a +2.50% grade at station 4 + 200 and elevation 164.657 m, 180-m curve, stakeout…

A:

Q: signment 5: Horizontal Curve Calculation: ation +26 3+00 7+00 5+00 5+68 = Station 18+26 signment 6:…

A:

Q: Two straight lines intersect at an angle of 60°. The radius of a curve joining the two straight…

A: Radius, R =600m  Intersection angle =60 ° Find  length of long chord=? mid-ordinates=?

Q: A-2.40% grade meets a +1.60% grade at station 44+25 and elevation 3387.96 ft, 400-ft curve, stakeout…

A: The initial grade of the curve = -2.4% The final grade of the curve = +1.6% The station of point of…

Q: fter a backsight on the PC with 0°00' set on the instrument, what is the deflection angle to the…

A: A backsight on the PC with 0.00' set on the instrument.To find:The deflection angle from the curve…

Q: Given the following information for a simple spiraled curve: o = 38°00'00" o Da = 4°30'00" o Ls =…

A: Simple spiraled curve:I =38oDa = 4o 30'Ls = 800 ftT.S. = Sta 35+00

Q: Station Line Length (Ft) Interior Angles A 89°30'30" AB 447.60 B 89°30'30" BC 180.00 C 89°45'45" CD…

A:

Q: A500-ft curve, grades of g +2.50% and 2 50% VPI at station 96 80 and elevation 839 26 ft, stakeout…

A: Length of curve, Grade 1, Grade 2, VPI station, Elevation of VPI, To find: The elevation of full…

Q: Given the arc distance (L) of a horizontal curve = 475.81' The degree of curve (Daº) = 06°-18'-18"…

A: Objective: To determine the deflection angle ∆ for the given horizontal curve.   Given: Arc distance…

Q: Arc length (L) = ?

A:

Q: Horizontal Curve Given: Radius (R) = 1654.35' %3D Degree of Curve (Da°) = 93°-27'-48" PC Station =…

A:

Q: A +4.90% grade meets a +1.55% grade at station 4+200 and elevation 605.568 m, 195-m curve, stakeout…

A: To calculate the station elevations, an equal tangent parabolic curve is given with the following…

Q: COURSE AB 8886 BC CD DA DISTANCE 120m ? 100m 80m 43. The length and bearing of BC 44. The area of…

A: here question contain multiple question so As per our guidelines i will answer only first question

Q: If you are standing at STA23+54.23, how many feet are you away from STA25+08.49 along the length of…

A: Starting Station (STA23+54.23)Ending Station (STA25+08.49)To find:The length of the alignment.

Q: Given the same vertical alignment connecting a -4% grade with a +2% grade with the PVC station at…

A:

Q: Horizontal Curve Given: Radius (R) = 1654.35' Degree of Curve (Daº) = 03°-27'-48" PC Station = 14 +…

A: A Curve is given. Radius, R = 1654.35' Degree of the curve, D = 3°27'48'' PC station = 14 + 27.62 To…

Curve setting

A curve is a turn that is provided horizontally or vertically in the design of highways, railways, and runways. A curve connects two straight lines that are separated by the deflection angle. It helps to change the direction and alignment of the highways, railway tracks, and runways. Therefore, the gradual change in their alignment is made by using a curve to provide comfort to the passengers and this also provides an easy turn to change the direction of the moving vehicle.