Given the following information for a simple spiraled curve I = 18°00’00” Da = 7°00’00” LS = 600 feet T.S. = Sta 43+00
Given the following information for a simple spiraled curve I = 18°00’00” Da = 7°00’00” LS = 600 feet T.S. = Sta 43+00
Chapter2: Loads On Structures
Section: Chapter Questions
Problem 1P
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Given the following information for a simple spiraled curve
I = 18°00’00”
Da = 7°00’00”
LS = 600 feet
T.S. = Sta 43+00
Assuming the throw distance, o, is 18.24 ft and Xo = 298.66 ft. Compute the tangent length, Ts, of the simple spiral curve, in feet.
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