Given the following information for a simple spiraled curve              I   = 18°00’00”             Da  = 7°00’00”             LS  = 600 feet             T.S.  = Sta 43+00

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Chapter2: Loads On Structures
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Given the following information for a simple spiraled curve

             I   = 18°00’00”
            Da  = 7°00’00”
            L = 600 feet

            T.S.  = Sta 43+00

Assuming the throw distance, o, is 18.24 ft and Xo = 298.66 ft. Compute the tangent length, Ts, of the simple spiral curve, in feet.

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