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Given the following groundwater analysis at 25 °C: Ca2+: 83.27 mg/L              Mg2+: 24.32 mg/L       Na+: 18.33 mg/L         K+: 2.34 mg/L                   SO42-: 23.45 mg/L       HCO3-: 366.78 mg/L Cl-: 12.50 mg/L                 pH = 7.8                      TDS = 542 mg/L 1) Do a cation-anion balance. 2)Find the ion activity product (IAP) of calcite CaCO3. 3)Compare the IAP of anhydrite with the Ksp of calcite (10-8.4)

Given the following groundwater analysis at 25 °C: Ca2+: 83.27 mg/L              Mg2+: 24.32 mg/L       Na+: 18.33 mg/L         K+: 2.34 mg/L                   SO42-: 23.45 mg/L       HCO3-: 366.78 mg/L Cl-: 12.50 mg/L                 pH = 7.8                      TDS = 542 mg/L 1) Do a cation-anion balance. 2)Find the ion activity product (IAP) of calcite CaCO3. 3)Compare the IAP of anhydrite with the Ksp of calcite (10-8.4)

Chemistry
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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Given the following groundwater analysis at 25 °C:

Ca2+: 83.27 mg/L              Mg2+: 24.32 mg/L       Na+: 18.33 mg/L        

K+: 2.34 mg/L                   SO42-: 23.45 mg/L       HCO3-: 366.78 mg/L

Cl-: 12.50 mg/L                 pH = 7.8                      TDS = 542 mg/L

1) Do a cation-anion balance.

2)Find the ion activity product (IAP) of calcite CaCO3.

3)Compare the IAP of anhydrite with the Ksp of calcite (10-8.4).

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