Given the following function: void printElement (int num[]) { printf("%d", num[@]); } What is the asymptotic (big-O notation) running time of this function? O O (log n) O O (n²) O 0 (1)
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- Java code: write a java code that can perform SQUARE-MATRIX-MULTIPLY-RECURSIVE. A; B(Strassen's Algorithms)/ and ordinary multiplication. The program should ask the user for input file and output file locations, and give output for both methods. It should also check if both outputs match and include error handing for incorrect Matrix Multiplication input.Write a function that takes in an integer n and computes n!. Do this without recursion. In [ ]: deffactorial_iter(n):"""Takes in an integer n>0 and returns the product of all integers from 1 to n."""# YOUR CODE HEREraiseNotImplementedError() In [ ]: In [ ]: assert factorial_iter(6) == 720 assert factorial_iter(7) == 5040 assert factorial_iter(10) == 3628800int getMax(int arr[], int n) { intmx=arr[0]; for (inti=1; i<n; i++) if (arr[i] >mx) mx=arr[i]; returnmx; } Can u give me the code for this one as well....this is the first function and countsort is the second
- sum = 0; for (int i = 1; i< n; i = sum++ || 2*i)In main() for now: do these - one at a time, each in it's own loop (we will make functions out of them later –Declare an array RandArray with 20 integers –Assign each of the 20 values with a random value from 0 to 99 Hint: Use rand()%100 For mimir: Do not call srand at the top of main. // normally: Call srand(time(0)) at the top of main –(you need #include<cstdlib>) –Write another loop that prints the array, with index values Important: If the output values do not match mimir, please add srand(17); // inside your main function - at the top code format: #include <iostream>using namespace std; #include <cstdlib> // required for rand() int main(){ srand(17); // define a constant ARRAYSIZE that is 20 // declare randArray // set the 20 elements in randArray to be a random number between 0 and 99 // hint: use rand()%100 // print the 20 values return 0;}+ genuity.com/player/ Semester A 1 1 2 2 3 4 5 3 return 1 else: 05 4 return n* factorial(n-1) Which line of code includes a recursive function call? O 3 04 01 Consider the Python code for finding the factorial of an integer n using recursion. Line numbers have been added to the left of each line of code. def factorial(n): if n == 1: Mark this and return O M B DELL A EXXI A Save and Exit 10 Next 2 G < ☆ 0 English V Sign out 19 Kinley Hea TIME REMAINING 50:49 Submit Mar 27 2:47
- One remarkably simple formula for calculating the value of p is the so-called Madhava-Leibniz series: p4 = 1-13+15-17+19-.... Consider the recursive function below to calculate the first n terms of this formula: double computePI(int n) { if (n <= 1) { return 1.0;} int oddnum = 2 * n - 1; if ((n % 2) == 0 { } return -1.0 oddnum + computePI(n − 1); } else { } return 1.0 / oddnum + computePI (n - 1); Which statements about the run-time performance of this function are true? 1.Each time this function is called it will invoke at least two more recursive calls II.The number of recursive calls this function will make is approximately equal to the value of the parameter variable n III.Not counting overhead, this function will be about as efficient as an iterative implementation of the same formula1. Given the following function: int Fn (int N) { } if (N == 0) return 2; else return N + Fn (N/3); a) What type of function is this, Iterative or Recursive? Give justification. b) Given N = 17, what will be the output from this function? Show your work.CodeW X bFor fun X C Solved x b Answer + x https://codeworko... CodeWorkout X265: Recursion Programmlng Exercise: GCD The greatest common divisor (GCD) for a pair of numbers is the largest positive integer that divides both numbers without remainder. For function GCD , write the missing base case condition and action. This function will compute the greatest common divisor of x and y.You can assume that x and y are both positive integers and that x > y. Greatest common divisor is computed as follows: = x and GCD(x, y) = GCD(y, x % y). Examples: GCD (6, 4) -> 2 Your An swer: 1 public int GCD(int x, int y) { if > { 2. > 3. } else { 4. return GCD(y, x % y); 9. { 7. 1:09 AM 50°F Clear 1V 1. 12/4/2021 甲
- le.com/forms/d/e/1FAlpQLSc6PlhZGOLJ4LOHo5cCGEf9HDChfQ-tT1bES-BKgkKu44eEnw/formResponse The following iterative sequence is defined for the set of positive integers: Sn/2 3n +1 ifn is odd if n is even Un = Using the rule above and starting with 13, we generate the following sequence: 13 u13 = 40 u40 =20 u20 = 10→ u10 =5 u5 = 16 u16 = 8 ug = 4 → Us =2 u2 =1. It can be seen that this sequence (starting at 13 and finishing at 1) contains 10 terms. The below function takes as input an integer n and returns the number of terms generated by the sequence starting at n. function i-Seq (n) u=n; i=%3; while u =1 if statement 1 u=u/2; else statement 2 end i=i+1; end statement 1 and statement 2 should be replaced by: None of the choices statement 1 is "mod(u,2)=D%3D0" and statement 2 is "u = 3*u+1;" statement 1 is "u%2" and statement 2 is "u = 3*u+1;" O statement 1 is "mod(n,2)=30" and statement 2 is "u = 3*n+1;"for (int i = 0;i>m2[i][j]; This C++ (2) ELä %3D :code used to Count from 0 to 2 O Print the array m2 O Read the array m2 OComplete the following function definition to recursively print the index of a unique value in an array or -1 if the value is not found:1 int getIndex(int *a, int s, int v) {2 if( ) { // if no values are found3 4 }5 if(a[s-1] == v) { // if a value is found6 7 }8 return getIndex( ); // recurse to check next value9 }Hint:Recurse through the array by counting down from size. 1. Complete the one line of code for line 2:2. Write one line of code for line 3:3. Write one line of code for line 6:4. Complete the one line of code for line 8: please send an atom code. not other software