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Given the following function header: def longest_chain(1st: list[int]) -> int: Given a list of integers, return the length of the longest chain of 1's that start from the beginning. Precondition: 1st is non-empty which one of the cases below is the least useful to check? Select the best answer. o longest chain((0]) O longest_chain([1, 1, O]) O longest_chain([1, 1,0, 1]) O longest_chain([1, 0, 1, 1]) longest_chain(['1; '1, o, '1, 1, 1])

Given the following function header: def longest_chain(1st: list[int]) -> int: Given a list of integers, return the length of the longest chain of 1's that start from the beginning. Precondition: 1st is non-empty which one of the cases below is the least useful to check? Select the best answer. o longest chain((0]) O longest_chain([1, 1, O]) O longest_chain([1, 1,0, 1]) O longest_chain([1, 0, 1, 1]) longest_chain(['1; '1, o, '1, 1, 1])

Database System Concepts
Database System Concepts
7th Edition
ISBN:9780078022159
Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Chapter1: Introduction
Section: Chapter Questions
Problem 1PE
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Given the following function header: def longest_chain(1st: list[int]) -> int: Given a list of integers, return the length of the longest chain of 1's that start from the beginning. Precondition: 1st is non-empty which one of the cases below is the least useful to check? Select the best answer. o longest chain([0]) O longest_chain([1, 1, O]) O longest_chain([1, 1, 0, 1]) O longest_chain([1, 0, 1, 1]) O longest_chain(['1', '1, '0, '1, '1, '1'])
Transcribed Image Text:Given the following function header: def longest_chain(1st: list[int]) -> int: Given a list of integers, return the length of the longest chain of 1's that start from the beginning. Precondition: 1st is non-empty which one of the cases below is the least useful to check? Select the best answer. o longest chain([0]) O longest_chain([1, 1, O]) O longest_chain([1, 1, 0, 1]) O longest_chain([1, 0, 1, 1]) O longest_chain(['1', '1, '0, '1, '1, '1'])
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