Given the following data, which membrane will have the highest Tm? 1:20:3 2:16:1 3: 18:0 4: 14:0 3 1 4 2

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**Question:** Given the following data, which membrane will have the highest Tm (melting temperature)?

1. 20:3  
2. 16:1  
3. 18:0  
4. 14:0  

**Options:**

- ○ 3  
- ○ 1  
- ○ 4  
- ○ 2  

**Explanation:**

In this context, the numbers represent fatty acid chains with the format X:Y, where X is the number of carbon atoms and Y is the number of double bonds. The Tm (melting temperature) is influenced by the length of the carbon chain and the degree of saturation (double bonds):

- **Longer carbon chains** generally result in a higher Tm because of increased van der Waals forces.
- **More double bonds** (unsaturation) generally result in a lower Tm due to kinks in the fatty acid chain that prevent tight packing.

**Analysis:**

- **20:3:** 20 carbons, 3 double bonds
- **16:1:** 16 carbons, 1 double bond
- **18:0:** 18 carbons, 0 double bonds (fully saturated)
- **14:0:** 14 carbons, 0 double bonds (fully saturated)

The fully saturated 18:0 with the longest chain and no double bonds is expected to have the highest Tm due to optimal packing and strong van der Waals forces. 

**Correct Answer:** ○ 3
Transcribed Image Text:**Question:** Given the following data, which membrane will have the highest Tm (melting temperature)? 1. 20:3 2. 16:1 3. 18:0 4. 14:0 **Options:** - ○ 3 - ○ 1 - ○ 4 - ○ 2 **Explanation:** In this context, the numbers represent fatty acid chains with the format X:Y, where X is the number of carbon atoms and Y is the number of double bonds. The Tm (melting temperature) is influenced by the length of the carbon chain and the degree of saturation (double bonds): - **Longer carbon chains** generally result in a higher Tm because of increased van der Waals forces. - **More double bonds** (unsaturation) generally result in a lower Tm due to kinks in the fatty acid chain that prevent tight packing. **Analysis:** - **20:3:** 20 carbons, 3 double bonds - **16:1:** 16 carbons, 1 double bond - **18:0:** 18 carbons, 0 double bonds (fully saturated) - **14:0:** 14 carbons, 0 double bonds (fully saturated) The fully saturated 18:0 with the longest chain and no double bonds is expected to have the highest Tm due to optimal packing and strong van der Waals forces. **Correct Answer:** ○ 3
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