Given the following code, what is the final value of variable 1 ? int i; for ( i=® ; i <= 4 ; i++ ) {) printf("i is:\n", i);
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- #include <stdio.h> #include <stdlib.h> double f(double x){ return x*x; } double reimannSums(double f(double), double a, double b, int n, double deltax) double sum=0.0, x; int i; printf("n = %d\n",nvoidvoid); for (i=0;i<n;i++){ x= ( (a+i*deltax)+a+(i+1)*deltax))/2; printf("x = %lf\n,x"); sum=sum + f(x); } return sum = (sum * deltax); double integ(double a, double b, double deltax) { double result; int n; n = (b - a) / deltax; return reimannSums(f, a, b, n, deltax); } int main(int argc, char * argv[]) { int a = atoi(argv[1]); int b = atoi(argv[2]); double deltax = atof(argv[3]); printf("result= %lf",integ(a, b, deltax)); } CAN YOU PLEASE CHECK MY WORK I GOT BUILD FAILED ERROR C LANGUAGE I NEED ANSWER IN 30 MIN THANKS<3#include int k=0; int f(int t) { k += t; heturn k; } void main() { int i, result=1; for(i = 1;i <= 3;i++) result = f(i); printf("%d\n", result); } A 3 B C) 1 D 123Find the value of M
- #include <stdio.h>int main(){int d;int s[20],i, r, p, lg=0,m;char c;printf("Enter number of salesman(max 20): ");scanf("%d", &d);for(i=0; i<d; i++){ printf("\n salesman %d sales: ");scanf("%d", &s[i]);}for(i=0; i<d; i++){for(r=i+1; j<d; r++){if(s[i] > s[r]){p= s[i];s[i] = s[r];s[j] = p;}}}printf("\nsalesman lowest to highest: ");for(i=0; i<d; i++){printf("%d\t", s[i]);}for(i=0;i<m;i++){printf("\n highest sales: %d ",lg);if(lg<=s[i])lg=s[i];break;}getch();} >>> the upper part output should be like this enter number of salesman (max 20): 5 salesman 1 500 salesman 2 300 salesman 3 1000 salesman 4 200 salesman 5 1000 in the lower part the lowest to highest the output should become like this salesman 4 200 salesman 2 300 salesman 1 500 salesman 3 1000 salesman 5 1000 highest total sales : 2000Void Do1 (int: &, a. int &b) { a = 5; a = a + b; b = a + 2; } Int main() { Int x = 10; Do1 (x,x); Cout << x << endl; } The output of this program is#include int main() { } int a, b, c, i=0; for (c=0; c < 7; C++) { } for(b 0; b < c; b++) { } for(a 0; a < b; a++) { } return 0; shown above? printf("%d\n", i++); ) What is the final value of i in the code
- #include <stdio.h>void cubeByReference( int *nPtr ); // function prototypeint main( void ){ int number = 5; // initialize number printf("The original value of number is %d", number ); // pass address of number to cubeByReference cubeByReference( &number ); printf("\nThe new value of number is %d\n", number );} // end main void cubeByReference( int *nPtr ){ *nPtr = *nPtr* *nPtr* *nPtr;} passing argument by reference - We modify the code above 1- define a second argument (example "int number2 = 9") and a pointer to it 2- define a second function (addByReference) that adds number2 to number - passing both arguments by reference 3- print-out the result (that is in number) Upload the output and .c codeWhat value will be returned by the function if a = 8, b=12? %3D int func(int a, int b){ if(a>b){ return a+b; } else if(aio/courses/1443/quizzes/4601/take/questions/74256 Study the definition of the following two functions "Rate" and "Bonus" and answer the question below. int Rate (int one, int two) { int R = one; for (int i = 0; i 20) num2 num1 * 20 +R; %3D else numl = num2 * 10 + R; return num1 + num2; What is the output of the following code segment? cout << Bonus (3, 5); a hp 近SEE MORE QUESTIONS