Given the following augmented matrix which represents a linear system, solve the linear system using technology for 1, 2, 3, 4, and z. If there is an infinite number of solutions then express the solutions in terms of z as the parameter. If there isn't a solution, then be sure to put "no solution" in each answer. X1 2x1 + x1 3x₁ + 5x1 + x1 = x2 = x3 X4 = + X2 + 3x2 + + 4x2 + 6x2 + || 2= Calculator Submit Question 4x3 + 8x3 + 5x3 + 11x3 + 19x3 + 4x4 8x4 4x4 13x4 21x4 - - - - 8z = 14z = 12z = 21z = 37z = 21 46 18 69 111

Calculus: Early Transcendentals
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ISBN:9781285741550
Author:James Stewart
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Chapter1: Functions And Models
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Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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Can you explain the solution please Thank you Its math liner algebra
Given the following augmented matrix which represents a linear system, solve the linear system
using technology for 1, 2, 3, 4, and z. If there is an infinite number of solutions then express
the solutions in terms of z as the parameter. If there isn't a solution, then be sure to put "no
solution" in each answer.
x1 =
3
X1
2x1 +
X1
3x1 +
5x1 +
x2 =
#
x3 =
C4 =
++
2=
с
X2 + 4x3 +
3x2 +
8x3 +
5x3 +
4x2 + 11x3 +
6x2 + 19x3 +
Calculator
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4
4
++
4x4
8x4
4x4
13x4
21x4
5
-
Search or type URL
8z
21
14z = 46
12z
18
21z
69
37% = 111
A
A
6
MacBook Pro
|| || || || ||
&
7
*
8
9
tv
Transcribed Image Text:Given the following augmented matrix which represents a linear system, solve the linear system using technology for 1, 2, 3, 4, and z. If there is an infinite number of solutions then express the solutions in terms of z as the parameter. If there isn't a solution, then be sure to put "no solution" in each answer. x1 = 3 X1 2x1 + X1 3x1 + 5x1 + x2 = # x3 = C4 = ++ 2= с X2 + 4x3 + 3x2 + 8x3 + 5x3 + 4x2 + 11x3 + 6x2 + 19x3 + Calculator Submit Question 4 4 ++ 4x4 8x4 4x4 13x4 21x4 5 - Search or type URL 8z 21 14z = 46 12z 18 21z 69 37% = 111 A A 6 MacBook Pro || || || || || & 7 * 8 9 tv
Expert Solution
Step

The given equations are;

x1+x2+4x3+4x4-8z=21

2x1+3x2+8x3+8x4-14z=46

x1+5x3+4x4-12z=18

3x1+4x2+11x3+13x4-21z=69

5x1+6x2+19x3+21x4-37z=111.

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