Given the following array members: 10 2 7 16 4*apply the Heap sort on the above array and DRAW the tree in every stage*.
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Given the following array members: 10 2 7 16 4
*apply the Heap sort on the above array and DRAW the tree in every stage*.
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- 1. "Max-beapitx (create a max-heap from) the following array using the bottom-up, O(n), algorithm. Show the final order in the array. Array: 69 2 1 3 45 Array:please follow directionQuestion 11 mahuse c++ Full explain this question and text typing work only We should answer our question within 2 hours takes more time then we will reduce Rating Dont ignore this line
- C programming help get numbers from user using a struct that points(pointer) into a binary search tree and another pointer into a array to use merge sort on the array then prints out all the numbers and at what hight they are in the binary tree and also prints out the sorted arrayCircular Lists - C PROGRAM A linear list is being maintained circularly in an array c[0…n-1] with front, and rear set up as for circular queues. a) Draft a formula/algorithm in terms of front, rear, and n for the number of elements in the list.Lab 16 Implementing bubble sort In this lab, you will implement the bubble sort algorithm. The bubble sort is so called because it compares adjacent items, "bubbling" the smaller one up toward the beginning of the array. By comparing all pairs of adjacent items starting at the end of the array, the smallest item is guaranteed to reach the beginning of the array at the end of the first pass.The second pass begins again at the end of the array, ultimately placing the second smallest item in the second position. During the second pass, there is no need to compare the first and second items, because the smallest element is guaranteed to be in the first position.Bubble sort takes at most n - 1 passes for an array of n items. During the first pass, n - 1 pairs need to be compared. During the second pass, n - 2 pairs need to be compared. During the ith pass, n - i pairs need to be compared. During the last pass, n - (n - 1) or one pair needs to be compared. If, during any pass, no two…