Given the fault tree diagram, and probabilities given below, what is the probability P of the event occurring? (To two decimal places) P1 = 0.98 P2 = 1 x 10-3 P3 = 5 x 10-4 P4 = 3 x 10-3 P5 = 7 x 10-5 D- P1 P2- P3- P4- P5

A First Course in Probability (10th Edition)
10th Edition
ISBN:9780134753119
Author:Sheldon Ross
Publisher:Sheldon Ross
Chapter1: Combinatorial Analysis
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Given the fault tree diagram, and probabilities given below, what is the probability P
of the event occurring? (To two decimal places)
P1 = 0.98
P2 = 1 x 10-3
%D
P3 = 5 x 10-4
P4 = 3 x 10-3
P5 = 7 x 10-5
P1
P2-
P3-
P4-
P5
Transcribed Image Text:Given the fault tree diagram, and probabilities given below, what is the probability P of the event occurring? (To two decimal places) P1 = 0.98 P2 = 1 x 10-3 %D P3 = 5 x 10-4 P4 = 3 x 10-3 P5 = 7 x 10-5 P1 P2- P3- P4- P5
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