Given the equations of motion of forced vibration. 10.00000 0.00000 5.10000 -1.60000 0.00000 4.00000 {*(t)}+ {x(t) = 100.00000 cos(8.00000 t), -1.60000 1.60000 0.00000 The solution consist of homogeneous and particular parts. The particular solution x(t), part due to the forcing term is. -0.11813 {x,(1)} =| cos(8.00000 t) 0.00074 -0.27564 {x,(t)} =| cos(8.00000*t) 0.00173 O None 0.43315 {x,(t)} =| cos(8.00000*t) -0.00272 (x,(e)} = -0.15751 cos(8.00000 t) 0.00099
Given the equations of motion of forced vibration. 10.00000 0.00000 5.10000 -1.60000 0.00000 4.00000 {*(t)}+ {x(t) = 100.00000 cos(8.00000 t), -1.60000 1.60000 0.00000 The solution consist of homogeneous and particular parts. The particular solution x(t), part due to the forcing term is. -0.11813 {x,(1)} =| cos(8.00000 t) 0.00074 -0.27564 {x,(t)} =| cos(8.00000*t) 0.00173 O None 0.43315 {x,(t)} =| cos(8.00000*t) -0.00272 (x,(e)} = -0.15751 cos(8.00000 t) 0.00099
Elements Of Electromagnetics
7th Edition
ISBN:9780190698614
Author:Sadiku, Matthew N. O.
Publisher:Sadiku, Matthew N. O.
ChapterMA: Math Assessment
Section: Chapter Questions
Problem 1.1MA
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Question
![Time l
Given the equations of motion of forced vibration.
10.00000 0.00000
5.10000 -1.60000
100.00000
{x(t)}=
cos(8.00000 t),
0.00000 4.00000
-1.60000 1.60000
0.00000
The solution consist of homogeneous and particular parts. The particular solution x(t), part due to the forcing term is.
-0.11813
cos(8.00000 t)
0.00074
-0.27564
{x,(1)} =|
cos(8.00000 t)
0.00173
O None
0.43315
{x,(1)}=-0.00272
cos(8.00000*t)
-0.15751
{x,(1)} =
cos(8.00000*t)
0.00099](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F8bfe2be8-b608-4040-bc1c-022e76173998%2F4c9771ab-18d6-4f04-a6ef-d68b93a675ed%2Fvju24qd.bmp&w=3840&q=75)
Transcribed Image Text:Time l
Given the equations of motion of forced vibration.
10.00000 0.00000
5.10000 -1.60000
100.00000
{x(t)}=
cos(8.00000 t),
0.00000 4.00000
-1.60000 1.60000
0.00000
The solution consist of homogeneous and particular parts. The particular solution x(t), part due to the forcing term is.
-0.11813
cos(8.00000 t)
0.00074
-0.27564
{x,(1)} =|
cos(8.00000 t)
0.00173
O None
0.43315
{x,(1)}=-0.00272
cos(8.00000*t)
-0.15751
{x,(1)} =
cos(8.00000*t)
0.00099
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