Given the equation e^{2x}=52x^2e.Using Bisection method for solving the roots of non-linear eqaution, What will be the root if the initial limit boundary used is -10,+10? Choices: 0.12267 -3.11036 3.11036 -0.12267
Given the equation e^{2x}=52x^2e.Using Bisection method for solving the roots of non-linear eqaution, What will be the root if the initial limit boundary used is -10,+10? Choices: 0.12267 -3.11036 3.11036 -0.12267
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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Given the equation e^{2x}=52x^2e.Using Bisection method for solving the roots of non-linear eqaution, What will be the root if the initial limit boundary used is -10,+10?
Choices:
0.12267
-3.11036
3.11036
-0.12267
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