Given the electric field Ē = (y + 1)đx + (x – 1)ảy + 2ãz, find the potential difference between the points a. (2,–2,–1) and (0,0,0) b. (3,2, –1) and (-2, –3,4)
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A: Solution:-Given thatA=(-1, 3, 4) mB=(0, -2, 5) mVB=3 voltsE=3x2ax-yay+z-2az Vm
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A: Given that, potential is, V=14πε0qr Using concept of gradient we have, E→=-∇→V
Q: Given an electric potential of 1 V= 4 περ Γ find its corresponding electric field vector.
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Q: (e) [p, f(f)] (f) [â, Ħ] for general potential V (x)
A: [?,?(?)]?=(??(?)−?(?)?)?[p,F(x)]ψ=(pF(x)−F(x)p)ψ knowing that ?=−?ℏ∂∂?p=−iℏ∂∂x you'll get…
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Q: potential xy? – 3x, what is the corresponding electric field at the point (1,8)?
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Q: Compute for the work done, in millijoules, in moving a 9-nC charge from A(-1, 1, 3) m to B(-1, -4,…
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Q: Given: ρL = 75 nC/m along the line x=2 and y=1, Q1 = 100 nC at (2,-3,0), Q2 = 100 nC at (1,2,0), ρS…
A: To find total work done, we find work done by individual components and then finally add them up.
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